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Norma-Jean [14]
3 years ago
12

Can someone please help me!!!!

Mathematics
1 answer:
Schach [20]3 years ago
6 0
<h2>Answer:</h2>

its 83

i have no explanation

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Let $P$ and $Q$ be constants. The graphs of the lines $x + 5y = 7$ and $15x + Py = Q$ are perpendicular and intersect at the poi
Marta_Voda [28]

Answer:

<em>(-3, -129)</em>

<em></em>

Step-by-step explanation:

Given

Two lines:

$x + 5y = 7$

$15x + Py = Q$

are perpendicular to each other and intersect at point (-8,3).

To find: (P, Q)

Solution:

The two lines intersect at (-8,3).

It means, the equation of line will be satisfied when we put value of x = -8 and y = 3

Putting in the second equation, we will get an equation in P and Q:

15\times (-8) + P \times 3 = Q\\\Rightarrow 3P = Q +120 ..... (1)

Given that two lines are perpendicular.

It means the product of their slopes will be equal to -1.

i.e. m_1\times m_2=-1

Slope of a line of the form ax+by+c=0 is given as:

m=-\dfrac{a}{b}

So, slopes of given lines are:

m_1=-\dfrac{1}{5}\\m_2=-\dfrac{15}{P}

Using the condition:

-\dfrac{1}{5}\times \dfrac{-15}{P}=-1\\\Rightarrow P = -3

Putting the value of P in equation (1):

\Rightarrow 3\times (-3) = Q +120 \\\Rightarrow Q = -9-120 = -129

So, answer is <em>(-3, -129)</em>

7 0
3 years ago
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