Answer:
C. It is a male with atleast one dominant allele
Explanation:
In the given pedigree, the two normal parents of the generation I have one daughter with the attached earlobe. Since the trait is recessive, the daughter should be homozygous recessive to express the trait. The genotype of the daughter (shaded circle in generation II) is "aa". To have a daughter with "aa" genotype, both the parents should have one copy of "a" allele. So, the genotype of both parents is "Aa".
In generation II, individual A is non-shaded square. Squares represent males in a pedigree. Since its not shaded, it does not have attached earlobe. Both the parents are heterozygous dominant for attached earlobes (Aa x Aa = 1/4 AA : 1/2 Aa : 1/4 aa). The genotype of this individual may be AA or Aa.
Something that has proof and evidence to prove it.
The Cell is the building block of the body
Know -
Transmitted through droplets
Has a range of side effects (loss of taste and smell, fever, etc)
People can be asymptomatic
Wonder -
When will we be able to return to semi-normal life?
Will we have to take a shot every year (similar to the flu?)
Why do some coronavirus patients become long-haulers who have recurring symptoms for many months?
Learned -
The mechanics of mask-wearing
How an individual can help their society as a whole
Many members of the population are hesitant to listen to scientists
Answer: One parent is IAi and the other parent is IBi
Explanation: As this trait is codominant, the child can inherited IA, IB or i.
Tina has type O, which means she is ii and her sister is AB, so her genotype is IAIB. Now, to have a child with a recessive trait both parents has to carry at least one allele for the recessive, i. Rosa is type AB which means she had to have inherited one allele IA from one of her parents and the other IB from the other parent. Thus, one parent is IAi and the other is IBi.
