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ANEK [815]
3 years ago
12

Calculate unknown sides and angles Please need before 4oclock BST

Mathematics
1 answer:
Arte-miy333 [17]3 years ago
4 0
The unknown side (PR) is 72 (42^2+58^2=5,128, square root of 5,128 which is 71.6, but rounds up to 72)
Angle Q is 90
(I don't have correct calculator for the other angles)
Angle P is 58/72=Answer, sin-1answer

Angle R is 42/72=Answer, sin-1answer
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Ericel has $50 to spend for food for a birthday party. The birthday cake will cost $17, and he also wants to buy 4 bags of chips
kaheart [24]

Answer:

17+4x <_ 50

Step-by-step explanation:

To solve the highest price Eric would pay for chips you would want to guess and check to get $8 is the most you can pay for each bag of chips

3 0
3 years ago
1. Let the test statistics Z have a standard normal distribution when H0 is true. Find the p-value for each of the following sit
Nonamiya [84]

Answer:

1 a  p -value  =   0.030054

1b   p -value  =   0.0029798

1c  p -value  = 0.0039768  

2a  p-value  =   0.00099966

2b  p-value  =  0.00999706

2c  p-value   = 0.0654412

Step-by-step explanation:

Considering question a

  The alternative hypothesis is H1:μ>μ0

   The test statistics is  z =1.88

Generally from the z-table  the  probability of   z =1.88 for a right tailed test is

    p -value  =  P(Z > 1.88) = 0.030054

Considering question b

  The alternative hypothesis is H1:μ<μ0

   The test statistics is  z=−2.75

Generally from the z-table  the  probability of   z=−2.75 for a left tailed test is

    p -value  =  P(Z < -2.75) = 0.0029798

Considering question c

  The alternative hypothesis is H1:μ≠μ0

   The test statistics is  z=2.88

Generally from the z-table  the  probability of  z=2.88 for a right  tailed test is

    p -value  = P(Z >2.88) =  0.0019884    

Generally the p-value for the two-tailed test is

    p -value  = 2 *  P(Z >2.88) =  2 * 0.0019884    

=> p -value  = 0.0039768  

Considering question 2a

    The alternative hypothesis is H1:μ>μ0

     The sample size is  n=16

     The  test statistic is  t =  3.733

Generally the degree of freedom is mathematically represented as

        df =  n - 1

=>     df =  16 - 1

=>     df =  15

Generally from the t distribution table  the probability of   t =  3.733 at a degree of freedom of  df =  15 for a right tailed test is  

       p-value  =  t_{3.733 ,  15} = 0.00099966

Considering question 2b

    The alternative hypothesis is H1:μ<μ0

     The degree of freedom is df=23

     The  test statistic is ,t= −2.500

Generally from the t distribution table  the probability of   t= −2.500 at a degree of freedom of  df=23 for a left  tailed test is  

       p-value  =  t_{-2.500 ,  23} = 0.00999706

Considering question 2c

    The alternative hypothesis is H1:μ≠μ0

     The sample size is  n= 7

     The  test statistic is ,t= −2.2500

Generally the degree of freedom is mathematically represented as

        df =  n - 1

=>     df =  7 - 1

=>     df =  6

Generally from the t distribution table  the probability of   t= −2.2500 at a degree of freedom of  df =  6 for a left   tailed test is  

       t_{-2.2500 , 6} = 0.03272060

Generally the p-value  for t= −2.2500 for a two tailed test is

     p-value  =  2 *  0.03272060 = 0.0654412

4 0
3 years ago
Find the measure of supplementary angles with measures 2x degrees and 7x degrees
LenKa [72]
2x+7x= 180
9x=180
x=20

Plug the x value in to both expressions
2(20)=40
7(20)=140

Final answer: 40 degrees, 140 degrees
3 0
3 years ago
Find the size of the angle a.<br><br> a=
miss Akunina [59]

a=72

Step-by-step explanation:

  • 2a+a+2a=360 (being complete turn )
  • 5a=360
  • a=360/5
  • a=72
6 0
3 years ago
Find the value of x for which I is parallel to m. The diagram is not to scale.
Marta_Voda [28]

Answer:

D

Step-by-step explanation:

3x - 43 = 80 (alternate angles)

7 0
4 years ago
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