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Nikitich [7]
2 years ago
15

n20=\sqrt{3}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
zepelin [54]2 years ago
5 0

tan( 20 ) + 4 Sin( 20 ) =

( Sin( 20 ) / Cos( 20 ) ) + 4 Sin( 20 ) =

Sin( 20 ) + 4 Sin( 20 ).Cos( 20 ) / Cos( 20 ) =

Sin( 20 ) + 2 × 2 Sin(20).Cos(20)/ Cos(20) =

Sin( 20 ) + 2 × Sin( 40 ) / Cos( 20 ) =

Sin( 20 ) + 2Sin( 40 ) / Cos( 20 ) =

Sin( 20 ) + 2Cos( 50 ) / Cos ( 20 ) =

Sin( 20 ) + 2Cos( 20 + 30 ) / Cos( 20 ) =

________________________________

2 × Cos( 30 + 20 ) =

2 × [ Cos(30).Cos(20) - Sin(30).Sin(20) ] =

2 × [ √3/2 × Cos(20) - 1/2 × Sin(20) ] =

√3 Cos(20) - Sin(20)

_________________________________

Sin( 20 ) + 2Cos ( 20 + 30 ) / Cos( 20 ) =

Sin( 20 ) + √3 Cos(20) - Sin(20) / Cos(20) =

Sin(20) - Sin(20) + √3 Cos(20) / Cos(20) =

0 + √3 Cos(20) / Cos(20) =

√3 Cos(20) / Cos(20) =

Cos(20) simplifies from the numerator and denominator of fraction

√3 × 1 / 1 =

√3

And we're done ....

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How do you solve 2(x+7)+x=20
alexira [117]
2(x+7) + x=20
(2)(x) + (2)(7) + x=20  Distribute 
2x+14 + x =20
(2x+x) + (14) =20  Combine Like Terms 
3x+14=20 
    - 14  -14             Subtract 14 from both sides 
3x = 6 
3x/3 6/3                  Divide Both Sides by 3 
 
x = 2 


Let me know if you still don't understand 

4 0
3 years ago
What would be the surface area of the figure..
valina [46]

Answer:

<h2>           503 cm²</h2>

Step-by-step explanation:

The surface area of the figure is sum of areas of two triangles and three ractangles:

A=2\cdot\frac12\cdot10\cdot8,3+3\cdot10\cdot14=83+420=503\,cm^2

8 0
3 years ago
Multiply the sum of -13/8 and 5/12 by their difference.​
REY [17]

Answer:

1421/576

Step-by-step explanation:

Sum = - 13/8 + 5/12 = - 39/24 + 10/24 = - 29/24

Difference = - 13/8 - 5/12 = - 39/24 - 10/24 = - 49/24

Sum * Difference = (-29/24)*(-49/24) = 1421/576

6 0
2 years ago
Jethro walked at an average speed of 3 miles per hour for 2 hours. Randy walked at an average of 4 miles per hour for 3 hours. W
Vedmedyk [2.9K]
C.
IS the answer
Ya... I think so
4 0
3 years ago
I need help I’m bad at math
Alina [70]
If you'd graph this function, you'd see that it's positive on [-1.5,0], and that it's possible to inscribe 3 rectangles on the intervals [-1.5,-1), (-1,-0.5), (-0.5, 1].

The width of each rect. is 1/2.

The heights of the 3 inscribed rect. are {-2.25+6, -1+6, -.25+6} = {3.75,5,5.75}.

The areas of these 3 inscribed rect. are (1/2)*{3.75,5,5.75}, which come out to:

{1.875, 2.5, 2.875}

Add these three areas together; you sum will represent the approx. area under the given curve on the given interval:  1.875+2.5+2.875 = ?
5 0
3 years ago
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