7/8 + _______ = 1...........

On three examinations, you have grades of 85, 78, and 84. There is still a final examination, which counts as one grade In order

Greeley [361]

Answer:

It's not possible to earn an A in the course
I must have a 73 or MORE to earn a B in the course

Step-by-step explanation:

The average obtained at the end of the course will be:

$\frac{85+78+84+x}{4} = av$

Where x is the grade obtained in the final examination and av is the final average. To obtain an A, av has to be at least 90, av≥90, and to obtain an B, av has to be at least 80, av≥80

Is an A in the course possible?

So, if we get 100 on the final average:

x = 100,

av = (85+78+84+100)/4 = 86,75 and 86,75∠90.

<em>Answer: No, the higher grade obtained would be 86,75.</em>

What grade you must have in the final to earn a B in the course

To earn a B, av≥80:

$av= \frac{85+78+84+x}{4 \ }\geq 80\\ \frac{247+x}{4}\geq80 \\247+x\geq 80*4\\ x\geq 320-247\\ x\geq 73$

<em>Answer: I must have a 73 or MORE to earn a B in the course</em>

6 0

4 years ago

A triangle has angles that measure 72.5 degrees and 32.7 degrees. What is the measure of the third angle?

astraxan [27]

72.5+32.7= 105.2
Triangle angles have to equal 180
180-105.2= 74.8
Third angle= 74.8 degrees

8 0

4 years ago

Read 2 more answers

Day care centers expose children to a wider variety of germs than the children would be exposed to if they stayed at home more o

Ostrovityanka [42]

Answer:

a) The study is an observational study

b) The proportion of children with significant social activity in children with acute lymphoblastic leukemia is approximately 0.802

The proportion of children with significant social activity in children without acute lymphoblastic leukemia is approximately 0.8565

c) The odds ratio is approximately 0.6780

d) The 95% CI is approximately 0.523 < OR < 0.833

e) i) Yes

ii) Children with more social activity have a higher occurrence of acute lymphoblastic leukemia

Step-by-step explanation:

a) An experimental study is a study in which the researcher adds inputs to the study and then monitors the outcomes

An observational study is one in which the researcher observes risk factors and does not intervene in the process

Therefore, the study is an observational study

b) The proportion of children with significant social activity in children with acute lymphoblastic leukemia is $\hat p_1$ = 1020/1272 = 85/106 = $0.8\overline {0188679245283}$ ≈ 0.802

The proportion of children with significant social activity in children without acute lymphoblastic leukemia is $\hat p_2$ = 5343/6238 ≈ 0.8565

c) We have the following two way table;

$\begin{array}{ccc}Lymphoblastic \ Leukemia &With \ Social \ Activity & Without \ Social \ Activity\\With&1020 \ (a)&252 \ (b)\\Without&5343 \ (c)&895 \ (d) \end{array}$

$The \ odds \ ratio = \dfrac{1,020 \times 895}{5,343 \times 252} \approx 0.6780$

The odds ratio ≈ 0.6780

d) The 95% confidence interval for the odds ratio is given as follows;

$95 \% \ CI = OR \ \pm \ 1.96 \times \sqrt{\dfrac{1}{a} +\dfrac{1}{b}+\dfrac{1}{c}+\dfrac{1}{d}}$

Where;

a = 1020, b = 252, c = 5343, d = 895

Therefore;

$95 \% \ CI \approx 0.6780 \ \pm \ 1.96 \times \sqrt{\dfrac{1}{1,020} +\dfrac{1}{252}+\dfrac{1}{5,343}+\dfrac{1}{895}} \approx 0.678 \pm0.155$

The 95% CI ≈ 0.523 < OR < 0.833

e) i) Given that the observed Odds Ratio is within the Confidence Interval, therefore, there is an indication that the amount of social activity is associated with acute lymphoblastic leukemia

ii) Based on the proportion of the study findings, children with more social activity have a higher occurrence of acute lymphoblastic leukemia

6 0

3 years ago

I want to cover the curved surface of a cylinder with orange paper. My cylinder is 14” tall. The diameter is 3.5”. I have listed

Dominik [7]

Circumference of the cylinder = 3.14 x 3.5 = 10.99 = 11 inches
so D. 11 x 14 is correct for the first part

area of the top = PI x r^2 = 3.14 x 1.75^2 = 9.62 inches

top and bottom = 9.62 x 2 = 19.23 = A. 19 inches

7 0

4 years ago

Paul high earns $5.00 an hour working part-time at an auto parts store he work 16 hours per week. What is his gross pay each wee

Nataly [62]

Answer:

$80

Step-by-step explanation:

$5 per hour, then for 16houurs. 5*16=80

6 0

3 years ago