The product of 9 and the quantity 5 more than a number t is less than 6
2 answers:
Answer:
Step-by-step explanation:
The product of 9 and the quantity 5 more than a number t is less than 6
Product represents the multiplication
the quantity 5 more than a number t is represented by t+5
The product of 9 and the quantity 5 more than a number t
The product of 9 and t+5 can be written as 9(x+5)
9(x+5) is less than 6
The given statement represents
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The point-slope form:
We have the point (-3, -1) and the slope m = 3/5. Substitute:
Answer:
point-slope form: y + 1 = 3/5(x + 3)
slope-intercept form: y = 3/5x + 4/5
standard form: 3x - 5y = -4
To solve the problem we could separate the figure into three parts. First figure is a triangle, second figure is a rectangle, third figure is a triangle. See image attached.
Solve each area of the figures
First figure, a triangle that have 7 units long of the base, and 2 units long of the height.
a = 1/2 × b × h
a = 1/2 × 7 × 2
a = 14/2
a = 7
The area of the first figure is 7 units²
Second figure is a rectangle, the length of the rectangle is 7 units, the width of the rectangle is 4 units.
a = l × w
a = 7 × 4
a = 28
The area of the second figure is 28 units²
Third figure is a triangle, the base is 7 units long and the height is 2 units long.
a = 1/2 × b × h
a = 1/2 × 7 × 2
a = 14/2
a = 7
The area of the third figure is 7 units²
The area of the three figures
area = first figure area + second figure area + third figure area
area = 7 + 28 + 7
area = 42
The total area of the figures is 42 units²
Solve each area of the figures
First figure, a triangle that have 7 units long of the base, and 2 units long of the height.
a = 1/2 × b × h
a = 1/2 × 7 × 2
a = 14/2
a = 7
The area of the first figure is 7 units²
Second figure is a rectangle, the length of the rectangle is 7 units, the width of the rectangle is 4 units.
a = l × w
a = 7 × 4
a = 28
The area of the second figure is 28 units²
Third figure is a triangle, the base is 7 units long and the height is 2 units long.
a = 1/2 × b × h
a = 1/2 × 7 × 2
a = 14/2
a = 7
The area of the third figure is 7 units²
The area of the three figures
area = first figure area + second figure area + third figure area
area = 7 + 28 + 7
area = 42
The total area of the figures is 42 units²