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kozerog [31]
3 years ago
5

Rocky has 7 bottles of water. He will buy more bottles of water from the store. The store has 8 cases in stock and each case con

tains 24 bottles of water. The store will not sell partial cases. The function that models the number of bottles of water Rocky will have after his purchase is f(c)=24c+7, where c is the number of cases of water he buys.
What is the practical domain of the function?


What is the practical domain of the function?

(a) {31, 55, 79, 103, 127, 151, 175, 199}{31, 55, 79, 103, 127, 151, 175, 199}

(b) {1, 2, 3, 4, 5, 6, 7, 8}{1, 2, 3, 4, 5, 6, 7, 8}

(c) all real numbers from 1 to 8, inclusive

(d) all real numbers
Mathematics
2 answers:
stepan [7]3 years ago
7 0

The practical domain of the function is all positive integer because c represents the number of case, and there is no negative number of case and it is not sold in partial so only positive integer can satisfy the given function. 

andreyandreev [35.5K]3 years ago
6 0

The <em><u>correct answer</u></em> is:

(b) {1, 2, 3, 4, 5, 6, 7, 8}

Explanation:

In this problem, we use the variable c to represent the independent quantity.  This means that the domain is all possible values for c.

Since the store only has 8 cases of water, the domain cannot be any number larger than 8.

Since the store only sells complete cases, not partial cases, of water, the domain cannot be a fraction or decimal number.

This means that the practical domain, or domain that makes sense for the problem situation, is {1, 2, 3, 4, 5, 6, 7, 8}.

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(sqrt(6))/(8+\sqrt(10))
valkas [14]

Answer:

\frac{4\sqrt{6}-\sqrt{15}}{27}

Step-by-step explanation:

\frac{\sqrt{6} }{8+\sqrt{10} } \\\\\mathrm{Multiply\:by\:the\:conjugate}\:\frac{8-\sqrt{10}}{8-\sqrt{10}}\\=\frac{\sqrt{6}\left(8-\sqrt{10}\right)}{\left(8+\sqrt{10}\right)\left(8-\sqrt{10}\right)}\\\\\sqrt{6}\left(8-\sqrt{10}\right)=8\sqrt{6}-2\sqrt{15}\\\left(8+\sqrt{10}\right)\left(8-\sqrt{10}\right)=54\\\\=\frac{8\sqrt{6}-2\sqrt{15}}{54}\\\\\mathrm{Factor}\:8\sqrt{6}-2\sqrt{15}:\quad 2\left(4\sqrt{6}-\sqrt{15}\right)\\\\=\frac{2\left(4\sqrt{6}-\sqrt{15}\right)}{54}\\

\mathrm{Cancel\:the\:common\:factor:}\:2\\\\=\frac{4\sqrt{6}-\sqrt{15}}{27}

5 0
3 years ago
The vertex angle of an isosceles triangle measures 40°. What is the measure of a base angle?
skad [1K]
In all triangles, inner angles add to 180 degrees.
In an isosceles triangle, the base angles are the same and the vertex angle is different from the rest.

b= (180-40)/2
b= 140/2
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Final answer: 70 degrees
8 0
3 years ago
Algebra tiles to prove that 4 + 8x and 4(2x+1)
Dafna1 [17]
Not sure what algebra tiles are

not sure how to absolutely prove
I can prove it works at least most of the time by subsitute ing number for x


remember that 0,1,2 have special properties and are not very good for subsituting so
try 4
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true or false?
4+8(4)=4(2(4)+1)
multipily
4+32=4(8+1)
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another way is to believe in the distributive property where
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7 0
3 years ago
Read 2 more answers
I need to know what is 190% of 40?
MrRissso [65]
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(40/x)*x=(100/190)*x
40=0.526315789474*x
(0.56315789474) to get x
40/0.536315789474=x
76=x
x=76 now we have 190% of 76


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Answer:

=14bx2−7x3−4b+2x

Step-by-step explanation:

8 0
3 years ago
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