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IceJOKER [234]
2 years ago
15

What is this answer to this

Mathematics
2 answers:
Irina-Kira [14]2 years ago
5 0
Your snswer is 14 2/3 I’m pretty sure
Leviafan [203]2 years ago
4 0
Your answer would be 14 and 2/3
You might be interested in
Select all expressions whose value is negative
il63 [147K]

Answer:

"2 + 2(-3)(7) = negative

-2(27 ÷ 9)+4= negative

(14 ÷ -2)(-6)= positive

(4 - 10) - ( 8 ÷ ( -2))= negative

Step-by-step explanation:

2 + 2(-3)(7) = -40

-2(27 ÷ 9)+4= -2

(14 ÷ -2)(-6)= 42

(4 - 10) - ( 8 ÷ ( -2))= -2"

5 0
3 years ago
P is a polynomial of degree 4 with three zeros: -1 and 2 are zeros of multiplicity one, and 3 is a zero with multiplicity two. I
tatyana61 [14]

Answer:

P(x) = (x+1)(x-2)(x-3)^2 + 108

Step-by-step explanation:

let me know if you want an explanation

3 0
2 years ago
What is one tenth of .2?
rosijanka [135]
The answer would be 0.02, I believe
5 0
3 years ago
Read 2 more answers
PLZ HELP, AND PLZ EXPLAIN
shutvik [7]

Answer:

C

Step-by-step explanation:

To make it easy let's start by organizing our information :

  • AC=12 AND BD=8
  • ABCD is a rhombus
  • K and L are the midpoints of sides AD and CD
  • we notice that the rhombus ABCD is divided into four right triangles

What do you think of when you hear a right triangle ?

  • The pythagorian theorem !

AC and BD  are khown so let's focus on them .

If we concentrated we can notice that AB and BD are cossing each other in the midpoints . why ?

Simply because they are the diagonals of a rhombus .

ow let's apply the pythagorian theorem :

  • (AC/2)² + (BD/2)² = BC²
  • 6²+4²=52
  • BC²= 52⇒\sqrt{52}=BC

Now we khow that : AB=BC=CD=AD=\sqrt{52}

This isn't enough . Let's try to figure out a way to calculate the length of KL  wich is the base of the triangle

  • KL is parallel to AC
  • k is the midpoint of AD and L of DC

I smell something . yes! Thales theorem

  • KL/AC=DL/DC=DK/AD WE4LL TAKE OLY ONE
  • KL/12=\sqrt{52}/2*\sqrt{52}  
  • KL/12=1/2⇒ KL=6

Now we have the length of the base kl

Now the big boss the height :

  • notice that you khow the length of KL
  • BD crosses kl from its midpoint and DL = \sqrt{52} /2

What I want to do is to apply the pythgorian thaorem to khow the lenght of that small part that is not a part of the height of the triangle . I will call it D

  • DL²=(KL/2)²+D²
  • 52/4= 9+ D²
  • D² = 52/4-9 +4 SO D=2

now the height of the trigle is H= BD-D= 8-2=6

NOw the area of the triangle is :

  • A=(KL*H)/2 ⇒ A= (6*6)/2=18

THE ANSWER IS 18 SQ.UN

5 0
3 years ago
"A new bakery offers decorated sheet cakes for children’s birthday parties and other special occasions. The bakery wants the vol
Darya [45]

Answer:

w = 9 \text{ inches}\\l = 13\text{ inches}\\h = 3\text{ inches}      

Step-by-step explanation:

We are given the following in the question:

Volume of cake = 351 cubic inches

Let x inches be the width of cake.

Width of cake, w =

x\text{ inches}

Then, length of cake,l =

(x + 4)\text{ inches}

Height of cake,h =

\dfrac{x}{3}\text{ inches}

Volume of cake = Volume of cuboid

V = lwh

Putting values, we get:

351 = x(x+4)(\dfrac{x}{3})\\\\1053 = x^3 + 4x\\x^3+4x^2-1053= 0\\\\\text{For x = 9}\\(9)^3+4(9)^2-1053= 0

Thus, dimensions of cake are:

w = 9 \text{ inches}\\l = 13\text{ inches}\\h = 3\text{ inches}

3 0
3 years ago
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