Answer:92.6013
Step-by-step explanation:
Answer:
Acceleration of the particle = 
Step-by-step explanation:
We are given the position vector of a particle moving in a circle of radius b units.
r(t) = b cos(ωt)i + b sin(ωt)j
Velocity , v =
= -bω sin(ωt)i + bω cos(ωt)j
The magnitude of velocity, v =
Squaring both sides,

Since
= 1

The acceleration towards the centre is called the centripetal acceleration and is given by
a = 
a = 
a = 