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olchik [2.2K]
2 years ago
13

Elsa and Anna share $2000 in the ratio 5 : 3. How much does each of them get?

Mathematics
1 answer:
Karolina [17]2 years ago
5 0

Answer:

Let them be "x"

5x+3x= $2000

8x= $2000

x= 2000/8

x= 250

5* 250= 1250.

3*250= 750.

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slega [8]
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y = x^{2} - 16
x = y^{2} - 16
x + 16 = y^{2}
\±\sqrt{x + 16} = \sqrt{y^{2}}
\±\sqrt{x + 16} = y
\±\sqrt{x + 16} = f^{-1}(x)
4 0
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In a one-month period, a convenience store
Vera_Pavlovna [14]
So, youd start by adding the two sales together to get total sales. Then you would divide that number by the gas sales to get the percent

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8 0
2 years ago
Solve for x. <br><br> x + 3x + 5 =21
timurjin [86]

Answer:

x=4

Step-by-step explanation:

In order to solve for x, we must isolate x on one side of the equation.

x+3x+5=21

First, combine like terms. x and 3x are both terms with variables, and can be combined.

(x+3x) + 5=21

4x + 5=21

5 is being added to 4x. The inverse of addition is subtraction. Subtract 5 from both sides of the equation.

4x+5-5= 21-5

4x= 16

x is being multiplied by 4. The inverse of multiplication is division. Divide both sides by 4.

4x/4=16/4

x= 16/4

x=4

Let's check our solution. Plug 4 in for x and solve.

x+3x+5=21

4+3(4)+5=21

4+12+5=21

16+5=21

21=21

This solution checks out, so we know our answer is correct.

x is equal to 4, x=4.

4 0
3 years ago
Read 2 more answers
3(4)<br> Solve 3(x-9)=21
Bas_tet [7]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
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Complete the proof of ∆JKL ≅ ∆LMN, by providing the reason for each of the statements below. Reasons MAY be used more than once.
aksik [14]

Answer:

  • See below

Step-by-step explanation:

1. JK ∥ LM, KL ∥ MN                                 Given

2. ∠KJL ≅ ∠MLN; ∠KLJ ≅ ∠MNL           c. Corresponding Angles  

3. JK ≅ LM                                               Given

4. ∆JKL ≅ ∆LMN                                     e. AAS

5 0
2 years ago
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