<h2>
Answer:</h2>
F = 13
<h2>
Explanation:</h2>
Given:
x = false
y = 5
z = 1
F = (4%2)+2*Y +6/2 +(z&&x)
We solve this arithmetic using the order of precedence:
<em>i. Solve the brackets first</em>
=> (4 % 2)
This means 4 modulus 2. This is the result of the remainder when 4 is divided by 2. Since there is no remainder when 4 is divided by 2, then
4 % 2 = 0
=> (z && x)
This means (1 && false). This is the result of using the AND operator. Remember that && means AND operator. This will return false (or 0) if one or both operands are false. It will return true (or 1) if both operands are true.
In this case since the right operand is a false, the result will be 0. i.e
(z && x) = (1 && false) = 0
<em>ii. Solve either the multiplication or division next whichever one comes first.</em>
=> 2 * y
This means the product of 2 and y ( = 5). This will give;
2 * y = 2 * 5 = 10
=> 6 / 2
This means the quotient of 6 and 2. This will give;
6 / 2 = 3
<em>iii. Now solve the addition by first substituting the values calculated earlier back into F.</em>
F = (4%2)+2*Y +6/2 +(z&&x)
F = 0 + 10 + 3 + 0
F = 13
Therefore, the value of F is 13
D I,II and III is the answer i think
Answer:
False
Explanation:
The private member of a class is not accessible by using the Dot notation ,however the private member are those which are not accessible inside the class they are accessible outside the class .The public member are accessible inside the class so they are accessible by using the dot operator .
<u>Following are the example is given below in C++ Language </u>
#include<iostream> // header file
using namespace std;
class Rectangle
{
private:
double r; // private member
public:
double area()
{ return 3.14*r*r;
}
};
int main()
{
Rectangle r1;// creating the object
r1.r = 3.5;
double t= r1.area(); // calling
cout<<" Area is:"<<t;
return 0;
}
Output:
compile time error is generated
<u>The correct program to access the private member of class is given below </u>
#include<iostream> // header file
using namespace std;
class Rectangle
{
private:
double r; // private member
public:
double area()
{
r1=r;
double t2=3.14*r2*r2;
return(t2); // return the value
}
};
int main()
{
Rectangle r1;// creating the object
r1.r = 1.5;
double t= r1.area(); // calling
cout<<" Area is:"<<t;
return 0;
}
Therefore the given statement is False
A- overusing highlights lowers the contrast and degrads the effect of the highlights.
I dont think it would, but maybe you should Google it just in case.
