3 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! I CANNOT RETAKE THIS!!

Mathematics

2 answers:

Misha Larkins [42]3 years ago

4 0

$y^3+2y^2+16y+32=\\\\y^2(y+2)+16(y+2)=\\\\(y+2)(y^2+16)=\\\\(y+2)(y-4i)(y+4i)$

iren [92.7K]3 years ago

3 0

The answer is
(y+2) (y^2+16)
This is because first factor out common terms i. the first two terms, then in the last two terms. Factor out the common term y+2

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