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3 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! I CANNOT RETAKE THIS!!

Mathematics

2 answers:

Misha Larkins [42]3 years ago

4 0

$y^3+2y^2+16y+32=\\\\y^2(y+2)+16(y+2)=\\\\(y+2)(y^2+16)=\\\\(y+2)(y-4i)(y+4i)$

iren [92.7K]3 years ago

3 0

The answer is
(y+2) (y^2+16)
This is because first factor out common terms i. the first two terms, then in the last two terms. Factor out the common term y+2

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2 Here are two equations:

MatroZZZ [7]

a. (3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. No, it is not possible to have more than one (x,y) pair that is solution to both equations

Step-by-step explanation:

a. Decide whether each neither of the equations,

i (3,4)

ii. (4,2.5)

ill. (5,5)

iv. (3,2)

To decide whether each point is solution to equations or not we will put the point in the equations

Equations are:

Equation 1: 6x + 4y = 34

Equation 2: 5x – 2y = 15

i (3,4)

Putting in Equation 1:

$6(3) + 4(4) = 34\\18+16=34\\34=34\\$

Putting in Equation 2:

$5(3) - 2(4) = 15\\15-8 = 15\\7\neq 15$

ii. (4,2.5)

Putting in Equation 1:

$6(4) + 4(2.5) = 34\\24+10=34\\34=34\\$

Putting in Equation 2:

$5(4) - 2(2.5) = 15\\20-5 = 15\\15=15$

ill. (5,5)

$6(5) + 4(5) = 34\\30+20=34\\50\neq 34$

Putting in Equation 2:

$5(5) - 2(5) = 15\\25-10 = 15\\15=15$

iv. (3,2)

$6(3) + 4(2) = 34\\18+8=34\\26\neq 34$

Putting in Equation 2:

$5(3) - 2(2) = 15\\15-4 = 15\\11\neq 15$

Hence,

(3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. Is it possible to have more than one (x, y) pair that is a solution to both

equations?

The simultaneous linear equations' solution is the point on which the lines intersect. Two lines can intersect only on one point. So a linear system cannot have more than one point as a solution

So,

a. (3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. No, it is not possible to have more than one (x,y) pair that is solution to both equations

Keywords: Linear equations, Ordered pairs

Learn more about linear equations at:

#LearnwithBrainly

8 0

3 years ago

Z= 37 51 39 Triangles and Trigonometry

san4es73 [151]

Answer:

$z = { \tan( \frac{10}{8} ) }^{ - 1} \\ z =(51.34019174591)$

So the corect answer is (51)

5 0

3 years ago

Find the equation of the line that passes through the points : (4 , -1 ) and (0 , -3)

Sergio [31]

Answer:

B. y= 1/2 x - 3

Step-by-step explanation:

base equation: y= mx+ b

slope(m) equation: $\frac{y_{2}-y_{2} }{x_{2} -x_{1} }$

y2= -1 y1= -3

x2= 4 x1= 0

$\frac{-1 - (-3)}{4-0} =\frac{2}{4} = \frac{1}{2}$

y- intercept: -3

found by taking the y from (0,-3)

3 0

3 years ago

F(x)=2x^3+2x-3 g(x)=-.5[x-4] what is the y value when f(x) = g(x)?

Charra [1.4K]

Answer:

D. x = 0.5

Step-by-step explanation:

A graphing calculator is the quickest way to get to an answer here.

f(x) = g(x) for x = 0.5

We can find the y-intercepts of the two functions to be ...

f(0) = -3

g(0) = -2

We know the x-intercept of g(x) is x=4. The x-intercept of f(x) will be a value less than 1, because f(1) = 1. (The function crosses the x-axis between x=0 where f(x) < 0 and x=1, where f(x) > 0.)

Considering these intercept points, we know the value of x for f(x)=g(x) will be between x=0 and x=1. There is only one answer choice in that interval:

x = 0.5

5 0

3 years ago

Select the description that is true to the equation x + y =2

lutik1710 [3]

Number one is correct

7 0

3 years ago