we are supposed to find
Which of these properties is enough to prove that a given parallelogram is also a Rectangle?
As we know from the theorem, if the diagonals of a parallelogram are congruent then the parallelogram is a rectangle.
The other options The diagonals bisect each other is not sufficient because in parallelogram diagonals always gets bisected , parallelogram becomes rectangles only if both the diagonals are of same length.
In a parallelogram The opposite angles and opposite sides are always equal.
Hence the correct option is
The diagonals are congruent.
Answer:
y=2, x=-1
Step-by-step explanation:
We can add the two equations together to eliminate x:
6x+5y+(-6x)+7y=4+20
12y=24
y=2
We plug y into the first equation and get
6x+5(2)=4
6x+10=4
6x=-6
x=-1
I hope you understood....if not...comment and I will be willing to still help
It would be 2/3 because 2 divided by 3 on a calculator is .6667
Answer:
The answer is the last one.
Step-by-step explanation:
Firstly, look at the first inequality and we get , so . In the second inequality, we have , so . Together, we know that the answer is the last one.