I will give you everything I can do:
11)
Lets say Car A travels at x mph. That means Car B travels at x+2 mph.
Both of them are traveling towards each others, so we can say the total speed is 2x+2.
Now i takes 3 hrs and we know the distance.
Since R*T=D
Then 3(2x+2)=270
So 2x+2=90
2x=88
x=44
12)
To find perpendicular we want to find the opposite reciprocal of the original slope. Therefore the slope is 3/2.
Now we must find the equation of the line with the given variable.
First find b.
5=3/2*4+b
b = -1
So the equation of this line is:
y=3/2x-1
13) All work will be shown below.
6-3(-2-4x)=2(3(x-4)+7)
6+6+12x=2(3x-12+7)
12+12x=2(3x-5)
12+12x=6x-10
6x=-2
x = -1/3
14)
First we must find the amount each train traveled.
The speed of F train(Freight train)=x
The speed of P train(passenger train)=x+6
Their combined speed is 2x+6
It takes 2 hrs to cover 100 miles
So 2(2x+6)=100
2x+6=50
2x=44
x=22
So the freight train covered 44 miles and the passenger train covered 56 miles.
To find average speed you must do Total Distance/Total Time.
44/2 and 56/2
Which are 22 and 28.
The average speed of F train is 22 mph and average speed of P train is 28 mph.
15) Again opposite reciprocal.
3/5 -> -5/3
Work:
-4=-3*-5/3+b
-4=5+b
b=-9
y = -5/3x-9
16)
F=kx-kx0
First kx0 = 0
So F=kx
So x=F/k
Intuitively, one would think the ball would land in the green spot 2 out of the 38 times, since there are 38 slots and 2 are green.
The probability that it lands in a green section is 2/38. Multiplying this by the number of times the experiment is performed, we get (2/38)(38) = 2.
Answer:
<u>The answer is option C. 6a-7</u>
Step-by-step explanation:
Given that
5(3a-1)-2(3a-2)=3(a+2)+v
Solve for v
∴ v = 5(3a-1)-2(3a-2) - 3(a+2)
∴ v = 15a - 5 - 6a + 4 - 3a - 6
∴ v = 15a - 6a - 3a - 5 + 4 - 6
∴ v = 6a - 7
<u>So the answer is option C. 6a-7</u>
Answer:
(0,4)
Step-by-step explanation:
y intercept is where the line crosses the y axis
Answer:

Step-by-step explanation:
<h3><u>Given functions:</u></h3>
- f(x) = 4x² - 6
- g(x) = x² - 4x - 8
<h3><u>Solution:</u></h3>
Subtract both functions
(f-g)(x) = 4x² - 6 - (x² - 4x - 8)
(f-g)(x) = 4x² - 6 - x² + 4x - 8
Combine like terms
(f-g)(x) = 4x² - x² + 4x - 6 - 8
(f-g)(x) = 3x² + 4x - 14
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