Answer:
Step-by-step explanation:
Let the original fraction is: x/ x-1
And we have that:
- 4 is added to the numerator => new numerator is: x+4
- 3 is subtracted from the denominator => new denominator is: x -1-3 = x -4
the fraction itself is increased by 2
<=> 
= 
<=> 
Solve for X then we substitue into the original fraction
Answer:46
Step-by-step explanation:
Use BODMAS to solve this
First is to open the innermost bracket
6+(4x(5+(10÷2)))
6+(4×(5+5))
Then the next bracket
6+(4×(10)
Open the next bracket, then multiply before adding
6+40
=46
Answer:
10
Step-by-step explanation:
The number of tiles in the design is 1 + 2 + 3 + ...
We can model this as an arithmetic series, where the first term is 1 and the common difference is 1. The sum of the first n terms of an arithmetic series is:
S = n/2 (2a₁ + d (n − 1))
Given that a₁ = 1 and d = 1:
S = n/2 (2(1) + n − 1)
S = n/2 (n + 1)
Since S ≤ 60:
n/2 (n + 1) ≤ 60
n (n + 1) ≤ 120
n must be an integer, so from trial and error:
n ≤ 10
Mr. Tong should use 10 tiles in the final row to use the most tiles possible.
The correct answer is 10.
In order to evaluate any composite function, you need to first put the value in for the inside function. In this case f(x) is on the inside along with the number 3. So, we input 3 in for x in f(x).
f(x) = 2x + 1
f(3) = 2(3) + 1
f(3) = 6 + 1
f(3) = 7
Now that we have the value of f(3), we can stick the answer in for the outside function, which is g(x).
g(x) = (3x - 1)/2
g(7) = (3(7) - 1)/ 2
g(7) = (21 - 1)/2
g(7) = 20/2
g(f(3)) = 10
