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stiks02 [169]
4 years ago
14

The circle given by x^2+y^2-4x-10=0 can be written in standard form like this: (x-h)^2+y^2=14. What is the value of h in this eq

uation??
Mathematics
2 answers:
Lana71 [14]4 years ago
8 0

Answer: H=2

Step-by-step explanation:

we just need to complete the square for the x terms

gropu x terms

x^2-4x

take 1/2 of linear coefient and square it

-4/2=-2, (-2)^2=4

x^2-4x+4

factor

(x-2)^2

h=2

nevsk [136]4 years ago
4 0
We just need to complete the square for the x terms

gropu x terms
x^2-4x
take 1/2 of linear coefient and square it
-4/2=-2, (-2)^2=4

x^2-4x+4
factor
(x-2)^2
h=2
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