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Lapatulllka [165]
3 years ago
15

Write a linear equation that goes through the points (0,4) and (4,10). A. y =3⁄2x + 4 B. y =3⁄2x – 4 C. y =2⁄3x – 4 D. y =2⁄3x +

4
Mathematics
1 answer:
Elena L [17]3 years ago
4 0

Answer:

A

Step-by-step explanation:

To write the equation, find the slope of the line using the two points. Find the difference in y values over the difference in x values.

\frac{y_2-y_1}{x_2-x_1} = \frac{10-4}{4-0}=\frac{6}{4}=\frac{3}{2}

Write the equation using the slope m=3/2 and the point slope form.

y-y_1=m(x-x_1)\\y-10=\frac{3}{2}(x-4)

This is the equation of the line. You can convert it to slope intercept form:

y-10=\frac{3}{2}(x-4)\\y-10 = \frac{3}{2}x - 6\\y=\frac{3}{2}x +4

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Read 2 more answers
a. How wide must a wall footing be if the load is 9,500 pounds per foot of wall length, and the footing rests on a sandy gravel?
Phantasy [73]

Answer:

a) 38"

b) L = 5.7'

Step-by-step explanation:

a) Given

P = 9,500 lb/ft

Thick = 18"

We assume an allowable bearing pressure of σ = 3000 lb/sf

If Stress = Force / Area

σ = P/A

Solving for area

A = P/σ  ⇒  A = 9,500 lb/ft/3000 lb/sf

⇒  A = 3.167 sf,  or  3.167 ft wide, per foot of length.

⇒  A = 38" wide

We can see the pic 1 in order to understand the answer.

b) Given

P = 65,000 pounds = 65,000 lb

Thick = 18" = 1.5'

We assume an allowable bearing pressure of σ = 2000 lb/sf

If Stress = Force / Area

σ = P/A

Solving for area

A = P/σ  ⇒  A = 65,000 lb/2000 lb/sf

⇒  A = 32.5 sf

then A = L²  ⇒  L = √A = √(32.5 sf) = 5.7 ft

Finally L = 5.7'

We can see the pic 2 in order to understand the answer.

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