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Tcecarenko [31]
3 years ago
15

Part a : part b: part c : part d :

Mathematics
1 answer:
ExtremeBDS [4]3 years ago
7 0

Answer:

por

Step-by-step explanation:

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How much is 2 quaters+ one 5 cents + 1 dime + 2 cents equals?​
Romashka-Z-Leto [24]

Answer:

67 cents

Step-by-step explanation:

2 quarters: one quarter is 25 cents, so two will be 50 cents.

5 cents: Just 5 cents.

1 dime: A dime is 10 cents.

2 cents: 2 cents!

Add everything up: 50 + 5 + 10 +2 = 67 cents!

5 0
2 years ago
Read 2 more answers
1) Find AC using either the distance formula or the Pythagorean Theorem.
kap26 [50]

Answer:

1.  C) 2/5 or 4.47   if 2/5 means 2 sqrt(5)

2. sqrt(68)

Step-by-step explanation:

1.  using the pythagorean theorem

a^2 + b^2 = c^2

where a = distance AB = 4   b = BC = 2   and c = AC = ?

4^2 + 2^2 = c^2

16 + 4 = c^2

20 = c^2

take the square root of each side

sqrt(20) = c

sqrt(4) * sqrt(5) = c

2sqrt(5) = c


2.  using the pythagorean theorem

a^2 + b^2 = c^2

where a = distance AC = 8   b = BC = 2   and c = AB = ?

8^2 + 2^2 = c^2

64 + 4 = c^2

68 = c^2

take the square root of each side

sqrt(68) = c

sqrt(4) * sqrt(17) = c

2sqrt(17) = c

did you forget to put the square root of B

5 0
4 years ago
Read 2 more answers
. A painter mixes two and a half pints of yellow paint with 4 pints of red paint to make a certain shade of orange paint. How ma
spin [16.1K]

Answer:

6

Step-by-step explanation:

A painter mixes 2 1/2 pints (2.5 pints) of yellow paint with 4 pints of red paint to make a certain shade of orange paint. The ratio of yellow paint to red paint is 2.5:4. In order to find the pints of yellow paint needed to be mixed with 10 pints of red paint, we will use conversion fractions.

10 red pints × (2.5 yellow pints/ 4 red pints) ≈ 6 pints (we round off to 1 significant figure)

5 0
3 years ago
Determine the shaded areas part 2​
shutvik [7]

9514 1404 393

Answer:

  (a) cannot be determined

  (b) 44 cm^2

  (c) 87 m^2

  (d) 180 m^2

  (e) 132 m^2

Step-by-step explanation:

(a) missing a horizontal dimension

__

(b) The difference between the bounding rectangle and the lower-left cutout is ...

  (8 cm)(7 cm) -(3 cm)(4 cm) = (56 -12) cm^2 = 44 cm^2

__

(c) The difference between the bounding rectangle and the center cutout is ...

  (13 m)(7 m) -(4 m)(1 m) = (91 -4) m^2 = 87 m^2

__

(d) The difference between the bounding rectangle and the two cutouts is ...

  (20 m)(25 m) -(16 m)(20 m) = (20 m)(25 -16) m = (20 m)(9 m) = 180 m^2

__

(e) The difference between the bounding rectangle and the two cutouts is ...

  (14 m)(12 m) -(12 m)(3 m) = (12 m)(14 -3) m = (12 m)(11 m) = 132 m^2

3 0
3 years ago
A-b
Lynna [10]

Answer:

\boxed{\sf d. \ \frac{a}{b}  =  \frac{10}{7}}

Step-by-step explanation:

\sf \implies \dfrac{a - b}{b}  =  \dfrac{3}{7}  \\  \\  \sf \implies  \frac{a}{b}  -  \frac{b}{b}  =  \frac{3}{7}  \\  \\  \sf \implies  \frac{a}{b}  - 1 =  \frac{3}{7}  \\  \\  \sf \implies  \frac{a}{b}  - 1 + 1 =  \frac{3}{7}  + 1 \\  \\  \sf \implies  \frac{a}{b}  =  \frac{3}{7}  + 1 \\  \\  \sf \implies  \frac{a}{b}  =  \frac{3}{7}  +  \frac{7}{7}  \\  \\  \sf \implies  \frac{a}{b}  =  \frac{3 + 7}{7}  \\  \\  \sf \implies  \frac{a}{b}  =  \frac{10}{7}

6 0
3 years ago
Read 2 more answers
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