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3 years ago

On a map, 1 inch equals 10 miles. If two cities are 2 inches apart on the map, how far are they actually apart?

Mathematics

1 answer:

Ulleksa [173]3 years ago

6 0

Answer:

20 miles

Step-by-step explanation:

If a map shows 1 inch is equal to 10 miles the 2 inches would be 10x2 which equals 20 miles.

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Explain how you could use a number line to show that -4 + 3 and 3 + (-4) have the same value. Which property of addition states

gtnhenbr [62]

I would say commutative.

8 0

2 years ago

Read 2 more answers

At a restaurant, you order a meal that costs $8. you leave a 15% tip. the sales tax is 6%. what is the total cost of the meal?

Oksi-84 [34.3K]

Easy! multiply the 6% by $8 then add it to the $8, now, multiply the 15% by the total of the cost with tax. then you all that to the total. ($9.75)

8 0

2 years ago

A private and a public university are located in the same city. For the private university, 1038 alumni were surveyed and 647 sa

Snezhnost [94]

Answer:

The difference in the sample proportions is not statistically significant at 0.05 significance level.

Step-by-step explanation:

Significance level is missing, it is α=0.05

Let p(public) be the proportion of alumni of the public university who attended at least one class reunion

p(private) be the proportion of alumni of the private university who attended at least one class reunion

Hypotheses are:

$H_{0}$ : p(public) = p(private)

$H_{a}$ : p(public) ≠ p(private)

The formula for the test statistic is given as:

z= $\frac{p1-p2}{\sqrt{{p*(1-p)*(\frac{1}{n1} +\frac{1}{n2}) }}}$ where

p1 is the sample proportion of public university students who attended at least one class reunion ( $\frac{808}{1311}=0.616$ )

p2 is the sample proportion of private university students who attended at least one class reunion ( $\frac{647}{1038}=0.623$ )

p is the pool proportion of p1 and p2 ( $\frac{808+647}{1311+1038}=0.619$ )

n1 is the sample size of the alumni from public university (1311)

n2 is the sample size of the students from private university (1038)

Then z= $\frac{0.616-0.623}{\sqrt{{0.619*0.381*(\frac{1}{1311} +\frac{1}{1038}) }}}$ =-0.207

Since p-value of the test statistic is 0.836>0.05 we fail to reject the null hypothesis.

6 0

3 years ago

Simplify square roots (variables) please show work ;)

7nadin3 [17]

Answer:

$3x^{3}$ $\sqrt{6x}$

Step-by-step explanation:

$\sqrt{57x^{7} }$

$\sqrt{3^{2}*6x^{2} * x }$

$\sqrt{3x^{2} }$ $\sqrt{x^{6} }$ $\sqrt{6x}$

$3x^{3}$ $\sqrt{6x}$

5 0

3 years ago

Keenan scored 80 points on an exam that had a mean score of 77 points and a standard deviation of 4.9 points. Rachel scored 78 p

Artemon [7]

Answer:

Keenan's z-score was of 0.61.

Rachel's z-score was of 0.81.

Step-by-step explanation:

Z-score:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Keenan scored 80 points on an exam that had a mean score of 77 points and a standard deviation of 4.9 points.

This means that $X = 80, \mu = 77, \sigma = 4.9$