The first thing we must do for this case is to define variables:
x: the total mass of the chemical in the container
y: a sample of a chemical from a container
We have the following equation:
y = (3/10) x - 5 3/4
Then, for y = 39.1 we have:
39.1 = (3/10) x - 5 3/4
Clearing x:
(3/10) x = 39.1 + 5 3/4
(3/10) x = 44.85
x = (10/3) * (44.85)
x = 149.5 grams
Answer:
the total mass in grams of the chemical in the container before the scientist removed the sample of 39.1 grams was:
x = 149.5 grams.
(16+5)4÷2=42
21×4÷2=42
84÷2=42
42=42
that is were to but you answer
Answer: A = 2000(1.05)^5
Step-by-step explanation:
We would apply the formula for determining compound interest which is expressed as
A = P(1 + r/n)^nt
Where
A = total amount in the account at the end of t years
r represents the interest rate.
n represents the periodic interval at which it was compounded.
P represents the principal or initial amount deposited
From the information given,
P = $2000
r = 5% = 5/100 = 0.05
n = 1 because it was compounded once in a year.
t = 5 years
Therefore, the equation that shows how much money will be in the account after five years is
A = 2000(1 + 0.05/1)^1 × 5
A = 2000(1.05)^5
Answer:
The expectation of the policy until the person reaches 61 is of -$4.
Step-by-step explanation:
We have these following probabilities:
0.954 probability of a loss of $50.
1 - 0.954 = 0.046 probability of "earning" 1000 - 50 = $950.
Find the expectation of the policy until the person reaches 61.
Each outcome multiplied by it's probability, so:
The expectation of the policy until the person reaches 61 is of -$4.
Answer:
7^15
Step-by-step explanation:
7^5^3 = 7^(5*3) = 7^15
