Question

[50 points]

Answer 1

Answer:

$\sf \dfrac{1}{10}$

Step-by-step explanation:

From the table:

• Total number of Sophomores = 10
• Total number of students = 37
• Total number of Boys who are Sophomores = 1

$\sf Probability \ of \ an \ event \ occurring = \dfrac{Number \ of \ ways \ it \ can \ occur}{Total \ number \ of \ possible \ outcomes}$

$\sf \implies P(Sophomore)=\dfrac{10}{37}$

$\sf \implies P(Boy \cap Sophomore)=\dfrac{1}{37}$

$\begin{aligned}\sf P(Boy | Sophomore) & = \sf\dfrac{P(Boy \cap Sophomore)}{P(Sophomore)}\\\\ & = \sf \dfrac{1}{37} \div \dfrac{10}{37}\\\\ & = \sf\dfrac{1}{37} \times\dfrac{37}{10}\\\\ & = \sf\dfrac{1}{10}\end{aligned}$