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3 years ago

Please help! Urgent! What is the measure of angle B? -78° -92° -102° -282°

Mathematics

2 answers:

Step2247 [10]3 years ago

7 0

C i believe because 180 is the overall degree and 50+28=78 and 180-78=102

loris [4]3 years ago

5 0

102 because 50+28=78 and 180-78=102 I’m pretty sure this is right. Correct me if not.

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A, b, c, and d please

DIA [1.3K]

<h2>Answers / Step-by-step explanation:</h2><h3>a. What is the length of one side of the square.</h3>

Looking at the image, the radius (r) of the circle appears to cover half of the length of a side of the square. Hence, the side of the square has a length of 2r.

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<h3>b. The formula A= πr² is used to find the area of a circle. The formula A=4r² can be used to find the area of the square. Write the ratio of the area of the circle to the area of the square in the simplest form.</h3>

$Ratio=\frac{\pi r^{2} }{4r^2} =\frac{\pi}{4}$ .

Notice that the value "r²" disappears from the expression because is being multiplied and divided by it at the same time.

$Ratio=\frac{4\pi }{16} =0.7854.$

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c. Complete the table.

To complete each cell of the table, simply take the equation of the asked parameter and substitute the value of r by the number indicated in the title of the column. For example, column 3 should be filled out like this:

Area of Circle (units²): π(3)²or 9π.

Length of 1 Side of the Square: 2r= 2(3)= 6.

Area of Square (units²)= 4r²= 4(3)²= 36.

Ratio: $\frac{\pi}{4}$ .

Do the same for all the other columns.

The answers to the table are presented on the attached image.

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d. What can you conclude about the relationship between the area of the circle and the square?

They will always have the same value, π/4, regardless of the size of the square and circle. As long as the circle borders meet the square's at the middle of each side of the square, the relationship will be the same.

4 0

2 years ago

Un terreno rectangular cuyo ancho mide 20 mts menos que su largo. Su área del terreno es de 150 metros cuadrados. ¿Determina las

IrinaVladis [17]

Answer:

you are a good friend Sayed im not sure if I can get it done before I get my license back and the whole time we go back and be out in a bit I guess that was the best thing I ever heard of the beast's I have

7 0

2 years ago

A=L times W

Dovator [93]

A= 30ft, because you only have to multiply LxW= A that is equal to 2x15=30ft

8 0

3 years ago

What is the answer of. 4y+7>-x-3

lora16 [44]

I don’t know what u need to look for but I think for y
4y+7>-x-3
4y>-x-10
y>-1/4x-5/2

5 0

3 years ago

Please solve the problem

jek_recluse [69]

Treat the matrices on the right side of each equation like you would a constant.

Let 2X + Y = A and 3X - 4Y = B.

Then you can eliminate Y by taking the sum

4A + B = 4 (2X + Y) + (3X - 4Y) = 11X

==> X = (4A + B)/11

Similarly, you can eliminate X by using

-3A + 2B = -3 (2X + Y) + 2 (3X - 4Y) = -11Y

==> Y = (3A - 2B)/11

It follows that

$X=\dfrac4{11}\begin{bmatrix}12&-3\\10&22\end{bmatrix}+\dfrac1{11}\begin{bmatrix}7&-10\\-7&11\end{bmatrix} \\\\ X=\dfrac1{11}\left(4\begin{bmatrix}12&-3\\10&22\end{bmatrix}+\begin{bmatrix}7&-10\\-7&11\end{bmatrix}\right) \\\\ X=\dfrac1{11}\left(\begin{bmatrix}48&-12\\40&88\end{bmatrix}+\begin{bmatrix}7&-10\\-7&11\end{bmatrix}\right) \\\\ X=\dfrac1{11}\begin{bmatrix}55&-22\\33&99\end{bmatrix} \\\\ X=\begin{bmatrix}5&-2\\3&9\end{bmatrix}$

Similarly, you would find

$Y=\begin{bmatrix}2&1\\4&4\end{bmatrix}$

You can solve the second system in the same fashion. You would end up with

$P=\begin{bmatrix}2&-3\\0&1\end{bmatrix} \text{ and } Q=\begin{bmatrix}1&2\\3&-1\end{bmatrix}$

3 0

3 years ago