Answer:
6.96774193548
Step-by-step explanation:
-3(x-4) > 6(x-1)
-3x +12 > 6x -6
12+6 > 6x+3x
18 > 9x
x < 18/9
x < 2 so from this result the solution set for this inequality dont includes 3 as an element
Hi
f(x) = g(x) if -x²+3x-2 - ( -x+1) = 0
-x² +3x-2 +x-1 = 0
-x² +4x -3 = 0
To solve, tou have to use the general method of resolution of a quadratic fonction.
To determine if it's has a solution in R, let's calculate Δ
Δ = (4)² - 4 * (1) *(-3)
Δ = 16 +12
Δ= 28
as Δ≥ 0 so the function allow two solution within R
so S 1 = ( -4 +√28) / 2 S 2 = (-4 -√28 ) /2
S1 = ( -4 + 2√7) /2 S2 = (-4 - 2√7) /2
S1 = (2 (-2 +√7) /2 S2 2 (-2 -√7) /2
S1 = -2 +√7 S2 = -2 -√7
So the two function are equal twice. one for x = -2 +√7 and second x = -2-√7
if the ellipse has a major axis of 12 inches, that means its major radius is half that, or 6, and if its minor axis is 7, then its minor radius is half that, 3.5.
![\bf \textit{volume of an elliptical cylinder}\\\\ V=\pi ab h~~ \begin{cases} a=\textit{major axis radius}\\ b=\textit{minor axis radius}\\ h=height\\[-0.5em] \hrulefill\\ a=6\\ b=3.5\\ h=21 \end{cases} \\\\\\ V=\pi (6)(3.5)(21)\implies V\approx 1385.44236023309881816203](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bvolume%20of%20an%20elliptical%20cylinder%7D%5C%5C%5C%5C%0AV%3D%5Cpi%20ab%20h~~%0A%5Cbegin%7Bcases%7D%0Aa%3D%5Ctextit%7Bmajor%20axis%20radius%7D%5C%5C%0Ab%3D%5Ctextit%7Bminor%20axis%20radius%7D%5C%5C%0Ah%3Dheight%5C%5C%5B-0.5em%5D%0A%5Chrulefill%5C%5C%0Aa%3D6%5C%5C%0Ab%3D3.5%5C%5C%0Ah%3D21%0A%5Cend%7Bcases%7D%0A%5C%5C%5C%5C%5C%5C%0AV%3D%5Cpi%20%286%29%283.5%29%2821%29%5Cimplies%20V%5Capprox%201385.44236023309881816203)
