Answer: a replay attack, a replay attack is used so that the attacker can go sniff out the hash, and get whatever they are trying to get, then once it goes to the attacker it will go back to the original connection after replaying the hash
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Explanation:
A.)
we have two machines M1 and M2
cpi stands for clocks per instruction.
to get cpi for machine 1:
= we multiply frequencies with their corresponding M1 cycles and add everything up
50/100 x 1 = 0.5
20/100 x 2 = 0.4
30/100 x 3 = 0.9
CPI for M1 = 0.5 + 0.4 + 0.9 = 1.8
We find CPI for machine 2
we use the same formula we used for 1 above
50/100 x 2 = 1
20/100 x 3 = 0.6
30/100 x 4 = 1.2
CPI for m2 = 1 + 0.6 + 1.2 = 2.8
B.)
CPU execution time for m1 and m2
this is calculated by using the formula;
I * CPI/clock cycle time
execution time for A:
= I * 1.8/60X10⁶
= I x 30 nsec
execution time b:
I x 2.8/80x10⁶
= I x 35 nsec
1.
name = input("Enter your name: ")
num1 = int(input("Hello "+name+ ", enter an integer: "))
num2 = int(input(name+", enter another integer: "))
try:
if num1 % num2 == 0:
print("The first number is divisible by the second number")
else:
print("The first number is not divisible by the second number")
except ZeroDivisionError:
print("The first number is not divisible by the second number")
try:
if num2 % num1 == 0:
print("The second number is divisible by the first number")
else:
print("The second number is not divisible by the first number")
except ZeroDivisionError:
print("The second number is not divisible by the first number")
2.
import random, math
num1 = float(input("Enter a small decimal number: "))
num2 = float(input("Enter a large decimal number: "))
r = round(random.uniform(num1, num2), 2)
print("The volume of a sphere with radius " + str(r) + " is " + str(round(((4 / 3) * math.pi * (r ** 3)), 2)))
I hope this helps!
Is it a multiple choice answer? if so would like to see the answers as there are TONS of effective ways and if i list one it may not be in that list you have if its multiple choice.