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Andreas93 [3]
3 years ago
6

Which statement describes one drive?

Computers and Technology
1 answer:
Ipatiy [6.2K]3 years ago
6 0
One drive is microsofts storage service for holding files in the “cloud”. It offers users a simple way to store and sync various types of files with other people/devices on the internet.
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which two functions are performed at the llc sublayer of the osi data link layer to facilitate ethernet communication? (choose t
Ivahew [28]

Answer:

implements CSMA/CD over legacy shared half-duplex media; enables IPv4 and IPv6 to utilize the same physical medium; integrates Layer 2 flows between 10 Gigabit Ethernet over fiber and 1 Gigabit Ethernet over copper

Explanation:

I hope it helped . follow me on ig minisized._miyaa

8 0
3 years ago
So i'm trying to figure out why this code wont run can anyone help me
MaRussiya [10]

Answer:

<em><u>use</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>ope</u></em><em><u>ning</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>cl</u></em><em><u>osing</u></em><em><u> </u></em><em><u>tags</u></em><em><u> </u></em>

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8 0
3 years ago
Design and implement a class dayType that implements the day of the week in a program. The class dayType should store the day, s
Afina-wow [57]

The code is implemented based on the given operations.

Explanation:

#include <iostream>

#include <string>

using namespace std;

class dayType

{ private:

 string day[7];

 string presentDay;

 int numofDays;

public:

 void setDay(string freshDay);

 void printDay() const;

 int showDay(int &day);

 int nextDay(int day);

 int prevDay(int day) const;

 int calcDay(int day, int numofDays);    

 dayType()

 {

  day[0] = "Sunday";

  day[1] = "Monday";

  day[2] = "Tuesday";

  day[3] = "Wednesday";

  day[4] = "Thursday";

  day[5] = "Friday";

  day[6] = "Saturday";

  presentDay = day[0];

  numofDays = 0;

 };

 ~dayType();

};

#endif

#include "dayType.h"

void dayType::setDay(string freshDay)

{

  presentDay = freshDay;

}

void dayType::printDay()

{

  cout << "Day chosen is " << presentDay << endl;

}

int dayType::showDay(int& day)

{

  return day;

}

int dayType::nextDay(int day)

{

day = day++;

if (day > 6)

 day = day % 7;

switch (day)

{

case 0: cout << "The successive day is Sunday";

 break;

case 1: cout << "The successive day is Monday";

 break;

case 2: cout << "The successive day is Tuesday";

 break;

case 3: cout << "The successive day is Wednesday";

 break;

case 4: cout << "The successive day is Thursday";

 break;

case 5: cout << "The successive day is Friday";

 break;

case 6: cout << "The successive day is Saturday";

 break;

}

cout << endl;

return day;

}

 

int dayType::prevDay(int day)

{

day = day--;

switch (day)

{

case -1: cout << "The before day is Saturday.";

 break;

case 0: cout << "The before day is Saturday.";

 break;

case 1: cout << "The before day is Saturday.";

 break;

case 2: cout << "The before day is Saturday.";

 break;

case 3: cout << "The before day is Saturday.";

 break;

case 4: cout << "The before day is Saturday.";

 break;

case 5: cout << "The before day is Saturday.";

 break;

default: cout << "The before day is Saturday.";

}

cout << endl;

return day;

}

int dayType::calcDay(int addDays, int numofDays)

{

addDay = addDays + numofDays;

if (addDay > 6)

 addDay = addDay % 7;

switch(addDay)

{

case 0: cout << "The processed day is Sunday.";

 break;

case 1: cout << "The processedday is Monday.";

 break;

case 2: cout << "The processedday is Tuesday.";

 break;

case 3: cout << "The processedday is Wednesday.";

 break;

case 4: cout << "The processedday is Thursday.";

 break;

case 5: cout << "The processedday is Friday.";

 break;

case 6: cout << "The processedday is Saturday.";

 break;

default: cout << "Not valid choice.";

}

cout << endl;

return addDays;

}

4 0
3 years ago
I WILL GIVE BRAINLIEST TO WHO ANSWERS FIRST AND CORRECTLY.
bogdanovich [222]

Answer:

True

Explanation:

3 0
3 years ago
After the data are appropriately processed, transformed, and stored, what is a good starting point for data mining?
Oksana_A [137]

Data visualization

Data visualization is a good starting point for data mining. There are several approaches to data mining that supports smart decisions. Data visualization places data in a visual context. It extracts the data in a clear and understandable way without any form of reading or writing. Results are displayed in the form of pie charts, graphs, and any other statistical representation. Such multidimensional views of data aid in developing a preliminary understanding of the trends that are hidden in the data set.

7 0
3 years ago
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