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kumpel [21]
3 years ago
10

Find the area of the triangle below.

Mathematics
1 answer:
svp [43]3 years ago
5 0

Answer:

  (5/6)x²

Step-by-step explanation:

The area of a triangle is given by the formula

  A = (1/2)bh

Here, the base is 5/3x, and the height is x. So, the area is ...

  A = (1/2)(5/3x)(x) = (5/6)x²

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There is a 20% chance of thunderstorms tomorrow. Describe the likelihood of the event.
Pachacha [2.7K]

Answer:

Step-by-step explanation:

20% = 1/5 or 0.2

There is a 1/5 chance of a thunderstorm.

There really is no clear answer. I would try 0.2

8 0
3 years ago
Read 2 more answers
Which are steps in the process of completing the square used to solve the equation 3 – 4x = 5x2 – 14x? Check all that apply.
avanturin [10]
Add 4x over to 14x, 3=5x2- 18x then add 18x to the other side 3+ 18x= 5x2then divided each side by 5,( 3+18x/5=x2) then square root each side the answer to x would be the square root of 3+18x/5
6 0
3 years ago
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V1/V2=T1/T2. Solve for V1
Ahat [919]
V1=(T1/T2)*V2
In this problem, since you are given no actual numbers, the only thing you can do is multiply V2 over to get V1 alone. Since you can't cancel anything out, you are left with the answer above.
4 0
2 years ago
What is the answer please.... need help
mina [271]

Answer:

f\left(x\right)=x^3-6x^2+3x+10 is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Step-by-step explanation:

Given the function

f\left(x\right)=x^3-6x^2+3x+10

As the highest power of the x-variable is 3 with the leading coefficients of 1.

  • So, it is clear that the polynomial function of the least degree has the real coefficients and the leading coefficients of 1.

solving to get the zeros

f\left(x\right)=x^3-6x^2+3x+10

0=x^3-6x^2+3x+10              ∵  f(x)=0

as

Factor\:x^3-6x^2+3x+10\::\:\left(x+1\right)\left(x-2\right)\left(x-5\right)=0

so

\left(x+1\right)\left(x-2\right)\left(x-5\right)=0    

Using the zero factor principle

if  ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

x+1=0\quad \mathrm{or}\quad \:x-2=0\quad \mathrm{or}\quad \:x-5=0

x=-1,\:x=2,\:x=5

Therefore, the zeros of the function are:

x=-1,\:x=2,\:x=5

f\left(x\right)=x^3-6x^2+3x+10 is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Therefore, the last option is true.    

8 0
2 years ago
Solve: 6x + 10 = 4x -8. Determine how many solutions? (exactly one, infinitely many, no solution)
Vesnalui [34]
  • Answer:

<em>x = - 9</em>

  • Step-by-step explanation:

<em>6x + 10 = 4x - 8</em>

<em>6x - 4x = - 10 - 8</em>

<em>2x = - 18</em>

<em>x = - 18 : 2</em>

<em>x = - 9</em>

7 0
3 years ago
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