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kumpel [21]
3 years ago
10

Find the area of the triangle below.

Mathematics
1 answer:
svp [43]3 years ago
5 0

Answer:

  (5/6)x²

Step-by-step explanation:

The area of a triangle is given by the formula

  A = (1/2)bh

Here, the base is 5/3x, and the height is x. So, the area is ...

  A = (1/2)(5/3x)(x) = (5/6)x²

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Help please. I need this answer and you don’t have to explain it
wariber [46]

Answer:

y=-5x+22

Step-by-step explanation:

4 0
2 years ago
A research company desires to know the mean consumption of meat per week among people over age 40. A sample of 610 people over a
Papessa [141]

Answer: (3.0,\ 3.2)

Step-by-step explanation:

Confidence interval for population mean is given by :-

\overline{x}\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}  (1)

, where \overline{x} = Sample mean

z_{\alpha/2}= Critical z-value

\sigma = Population standard deviation.

n= Sample size.

As per given , we have

n= 610

\sigma=1.1

\overline{x}=3.1

Significance level for 85% confidence : \alpha=1-0.85=0.15

By z-table critical two tailed z-value : z_{\alpha/2}=z_{0.075}=1.44

Put all values in (1) , we get

3.1\pm 1.44\dfrac{1.1}{\sqrt{610}}

3.1\pm 1.44\dfrac{1.1}{24.698}

3.1\pm 0.064

=(3.1-0.064,\ 3.1+0.064)=(3.036,\ 3.164)\approx(3.0,\ 3.2)

Hence, the 85% confidence interval for the mean consumption of meat among people over age 40.  = (3.0,\ 3.2)

5 0
3 years ago
The distance d in miles that can be covered by a rabbit in X hours is given in the equation y = 30 x The distance covered by a b
AveGali [126]

Answer:

Rabbit is faster than bear.

Step-by-step explanation:

Speed of rabbit or bear is determined by their rate of change of their distances with time.

The distance covered by rabbit in x hours is given as:

y=30x

The above equation is of the form y=mx, where, m is the rate of change of y with x.

Therefore, the rate of change of rabbit's distance with time is 30 mi/h.

Now, from the graph, the slope is given as the rise over run.

Rise is 50 miles and run is 2 miles.

So, rate of change of bear's distance with time is, m_b=\frac{50}{2}=25\ mi/h

Now, 30 is greater than 25. So, rabbit is faster than bear.

6 0
3 years ago
Let a1, a2, a3, ... be a sequence of positive integers in arithmetic progression with common difference
Bezzdna [24]

Since a_1,a_2,a_3,\cdots are in arithmetic progression,

a_2 = a_1 + 2

a_3 = a_2 + 2 = a_1 + 2\cdot2

a_4 = a_3+2 = a_1+3\cdot2

\cdots \implies a_n = a_1 + 2(n-1)

and since b_1,b_2,b_3,\cdots are in geometric progression,

b_2 = 2b_1

b_3=2b_2 = 2^2 b_1

b_4=2b_3=2^3b_1

\cdots\implies b_n=2^{n-1}b_1

Recall that

\displaystyle \sum_{k=1}^n 1 = \underbrace{1+1+1+\cdots+1}_{n\,\rm times} = n

\displaystyle \sum_{k=1}^n k = 1 + 2 + 3 + \cdots + n = \frac{n(n+1)}2

It follows that

a_1 + a_2 + \cdots + a_n = \displaystyle \sum_{k=1}^n (a_1 + 2(k-1)) \\\\ ~~~~~~~~ = a_1 \sum_{k=1}^n 1 + 2 \sum_{k=1}^n (k-1) \\\\ ~~~~~~~~ = a_1 n +  n(n-1)

so the left side is

2(a_1+a_2+\cdots+a_n) = 2c n + 2n(n-1) = 2n^2 + 2(c-1)n

Also recall that

\displaystyle \sum_{k=1}^n ar^{k-1} = \frac{a(1-r^n)}{1-r}

so that the right side is

b_1 + b_2 + \cdots + b_n = \displaystyle \sum_{k=1}^n 2^{k-1}b_1 = c(2^n-1)

Solve for c.

2n^2 + 2(c-1)n = c(2^n-1) \implies c = \dfrac{2n^2 - 2n}{2^n - 2n - 1} = \dfrac{2n(n-1)}{2^n - 2n - 1}

Now, the numerator increases more slowly than the denominator, since

\dfrac{d}{dn}(2n(n-1)) = 4n - 2

\dfrac{d}{dn} (2^n-2n-1) = \ln(2)\cdot2^n - 2

and for n\ge5,

2^n > \dfrac4{\ln(2)} n \implies \ln(2)\cdot2^n - 2 > 4n - 2

This means we only need to check if the claim is true for any n\in\{1,2,3,4\}.

n=1 doesn't work, since that makes c=0.

If n=2, then

c = \dfrac{4}{2^2 - 4 - 1} = \dfrac4{-1} = -4 < 0

If n=3, then

c = \dfrac{12}{2^3 - 6 - 1} = 12

If n=4, then

c = \dfrac{24}{2^4 - 8 - 1} = \dfrac{24}7 \not\in\Bbb N

There is only one value for which the claim is true, c=12.

3 0
2 years ago
Find the difference <br> (6ab+4a-3) - (2ab-4)
Y_Kistochka [10]
This would be 8(ab) sooo yaaaa
3 0
3 years ago
Read 2 more answers
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