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3 years ago

Write a real-life word problem that matches the equation ( 1 5 ) ÷ 3 =

Mathematics

2 answers:

DerKrebs [107]3 years ago

8 0

Answer:

omg lol okay i love this:

Step-by-step explanation:

one day bob, billy, and sara went to the store to buy cookies.

they bought a box of 15 cookies.

THERE ARE TWO WAYS THIS STORY CAN GO:

NUMBER ONE:

bob, billy, and sara decided to split the bill. each cookie was one dollar. they each payed $5.

NUMBER TWO

when they got home, bob, billy, and sara decided to eat the cookies. they didn't know how to spilt them :(

they each took one cookie until they had an even amount. each child got 5 cookies.

THE END LOL I LOVE THIS

Kay [80]3 years ago

3 0

Answer:

55555555555555555566666

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The graph h = −16t^2 + 25t + 15 models the height and time of a ball that was thrown off of a building where h is the height in

Olenka [21]

Answer:

Step-by-step explanation:

If you graph the equation f(x) = -16x^2+25x+15. You would need to pay attention to the x value which is somewhere in between 0.75-0.9.

Another way is to convert the equation into vertex form.

6 0

3 years ago

Read 2 more answers

Consider the probability that greater than 26 out of 124 software users will call technical support. Assume the probability that

Mekhanik [1.2K]

Answer:

Since $n(1-p) = 3.72 < 10$ , the normal curve cannot be used as an approximation to the binomial probability.

100% probability that greater than 26 out of 124 software users will call technical support.

Step-by-step explanation:

Test if the normal curve can be used as an approximation to the binomial probability by verifying the necessary conditions.

It is needed that:

$np \geq 10$ and $n(1-p) \geq 10$

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .

Out of 124 software users

This means that $n = 124$

Assume the probability that a given software user will call technical support is 97%.

This means that $p = 0.97$

Conditions:

$np = 124*0.97 = 120.28 \geq 10$

$n(1-p) = 124*0.03 = 3.72 < 10$

Since $n(1-p) = 3.72 < 10$ , the normal curve cannot be used as an approximation to the binomial probability.

Consider the probability that greater than 26 out of 124 software users will call technical support.

The lowest possible probability of those is 27, so, if it is 0, since it is considerably below the mean, 100% probability of being greater. We have that:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 27) = C_{124,27}.(0.97)^{27}.(0.03)^{97} = 0$