The lengths of the line segments are summarized in the following list:
- DF = 3
- DE = 8 / 3
- FG = 3
- FH = 9 / 2
- GH = 3 / 2
- EH = - 11 / 6
<h3>How to calculate the length of a line segment based on point set on a number line</h3>
Herein we have a number line with five points whose locations are known. The length of each line segment is equal to the arithmetical difference of the coordinates of the rightmost point and the leftmost point:
DF = - 1 - (- 4)
DF = 3
DE = (- 1 - 1 / 3) - (- 4)
DE = 3 - 1 / 3
DE = 8 / 3
FG = 2 - (- 1)
FG = 3
FH = (3 + 1 / 2) - (- 1)
FH = 4 + 1 / 2
FH = 9 / 2
GH = (3 + 1 / 2) - 2
GH = 1 + 1 / 2
GH = 3 / 2
EH = (3 + 1 / 2) + (- 1 - 1 / 3)
EH = - 2 + (1 / 2 - 1 / 3)
EH = - 2 + 1 / 6
EH = - 11 / 6
To learn more on lengths: brainly.com/question/8552546
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Answer:
No
Step-by-step explanation:
Positives cannot point at negatives I think.
Answer:
each pack costs 2.5, she bought x packs
x=2+4+3=9
she bought 9 packs
so 2.5 times 9=22.50
she spend $22.50
Standard form: x-y = -3
x & y have to be whole numbers
x has to be positive
Answer:
![4ln [\frac{x^2 (x^3-1)}{x-5}]](https://tex.z-dn.net/?f=%204ln%20%5B%5Cfrac%7Bx%5E2%20%28x%5E3-1%29%7D%7Bx-5%7D%5D)
Step-by-step explanation:
For this case we have the following expression:
![4[ln(x^3-1) +2ln(x) -ln(x-5)]](https://tex.z-dn.net/?f=%204%5Bln%28x%5E3-1%29%20%2B2ln%28x%29%20-ln%28x-5%29%5D)
For this case we can apply the following property:
And we can rewrite the following expression like this:
And we can rewrite like this our expression:
![4[ln(x^3-1) +ln(x^2) -ln(x-5)]](https://tex.z-dn.net/?f=%204%5Bln%28x%5E3-1%29%20%2Bln%28x%5E2%29%20-ln%28x-5%29%5D)
Now we can use the following property:
And we got this:
![4[ln(x^3-1)(x^2) -ln(x-5)]](https://tex.z-dn.net/?f=%204%5Bln%28x%5E3-1%29%28x%5E2%29%20-ln%28x-5%29%5D)
And now we can apply the following property:
And we got this:
And that would be our final answer on this case.
