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3 years ago

-|36| + | 7 | = what is the value

2 answers:

8 0

The answer is -29. Since absolute value means the distance away from zero, the absolute value of a number is that number. Like the absolute value of 6 is 6. It is 6 spaces away from zero. If the negative I within I I, like I -6I, the absolute value of -6 is 6. But if the negative sigh is outside like this, -| 6|, the answer would be -6. It is inevitable that it would be negative. So in this case, keep the number and keep the sign outside of | |.

Vika [28.1K]3 years ago

5 0

-29 because negative plus positive = negative

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Add 3×+8y-12zand5x-7y+15z help meee

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3x+5x+12z+15z+8y+7y

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3 years ago

When 142 is added to a number, the result is 64 more times than 3 times the number. What is the number?

allsm [11]

x+142 =3x+64

subtract x from each side

142 = 2x+64

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78=2x

divide by 2

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4 years ago

Read 2 more answers

If necessaly, combine like terms. (3x+8)2

mel-nik [20]

Step-by-step explanation:

multiply 2 with the bracket numbers

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3 years ago

The area of room in a dollhouse is 1248 sq in. the width of the room is 8 in. how long is the room?

Tanzania [10]

The length of the room is 156 sq in

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3 years ago

What are the minimum, first quartile, median, third quartile, and maximum of the data set? 2, 13, 17, 14, 9, 3, 16, 12

Alex777 [14]

So before anything, rearrange the data so that it's in ascending order: {2,3,9,12,13,14,16,17}

Next, the minimum and maximum are as they seem: the smallest and largest numbers in the data. Looking at our data, 2 is our minimum and 17 is our maximum.

Next, to find the median, find the number that is in the middle of the data set. If there isn't one number in the middle, find the average of the two middle numbers to get your median:

$\{2,3,9,\overbrace{\boxed{12,13,}}^{\textsf{middle numbers}}14,16,17\}\\\\\frac{12+13}{2}\\\\\frac{25}{2}\\\\12.5$

The median is 12.5.

Next, to find the first quartile, or the lower quartile, find the "median" of the numbers to the left of the median.

$\overbrace{\{2,\boxed{3,9,}12,}^{\textsf{left of median}}13,14,16,17\}\\\\\frac{3+9}{2}\\\\\frac{12}{2}\\\\6$

The first quartile is 6.

Next, to find the third quartile, or the upper quartile, find the "median" of the numbers to the right of the median.

$\{2,3,9,12,\overbrace{13,\boxed{14,16,}17\}}^{\textsf{right of median}}\\\\\frac{14+16}{2}\\\\\frac{30}{2}\\\\15$

The third quartile is 15.

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3 years ago