Let A( t , f( t ) ) be the point(s) at which the graph of the function has a horizontal tangent => f ' ( t ) = 0.
But, f ' ( x ) = [ ( x^2 ) ' * ( x - 1 ) - ( x^2 ) * ( x - 1 )' ] / ( x - 1 )^2 =>
f ' ( x ) = [ 2x( x - 1 ) - ( x^2 ) * 1 ] / ( x - 1 )^2 => f ' ( x ) = ( x^2 - 2x ) / ( x - 1 )^2;
f ' ( t ) = 0 <=> t^2 - 2t = 0 <=> t * ( t - 2 ) = 0 <=> t = 0 or t = 2 => f ( 0 ) = 0; f ( 2 ) = 4 => A 1 ( 0 , 0 ) and A 2 ( 2 , 4 ).
<u>Given</u>:
Given that the circle with center O.
The radius of the circle is OB.
The chord of the circle O is PQ and the length of PQ is 12 cm.
We need to determine the length of the segment PA.
<u>Length of the segment PA:</u>
We know that, "if a radius is perpendicular to the chord, then it bisects the chord and its arc".
Thus, we have;

Substituting the value PQ = 12, we get;


Thus, the length of the segment PA is 6 cm.
Hence, Option d is the correct answer.
I believe the answer is Chord AB
Answer:
Rational,integer
Step-by-step explanation: