Answer:
PUSHIN
Step-by-step explanation:
Answer:
The angles are 110, 110 and 140
Step-by-step explanation:
Let the equal angles be x.
So we have angles x, x and another third one
Now, the other third angle is 30 degrees larger than x, this means that the other third angle is 30 + x
Since they are angles at a point, adding the three together will make or give 360.
Thus,
x + x + x + 30 = 360
3x + 30 = 360
3x = 360-30
3x = 330
x = 330/3
x = 110
So the other third angle is 110 + 30 = 140
So the angles are 110, 110 and 140
Answer: I think it’s D
Step-by-step explanation:
it’s because 8^2 + 13^2 equals 233 and when square rooted equals 15.26 not 20 so no.
Answer:
D. 1800°
Step-by-step explanation:
The given polygon has 12 sides.
The formula for finding the sum of the interior angles of an n-sided polygon is given as, ( n − 2 ) × 180.
Where n is the number of sides of the polygon.
Thus, the sum of the interior angles of the 12 sided polygon given above is:
(12 - 2) × 180
= 10 × 180 = 1800°
<em>Sum of the measures of the interior angles of the 12-sided polygon is D. 1800°</em>
Answer:
103= p small
plarge = 123
Step-by-step explanation:
We know that the the ratio of the areas is the scale factor squared/
Larger triangle over smaller triangle
72
----- = scale factor ^2
50
simplify by dividing by 2 on top and bottom
36
----- = scale factor ^2
25
Take the square root of each side
sqrt(36)
-------------- = sqrt(scale factor ^2)
sqrt(25)
6
-------------- = scale factor
5
The ratio of the perimeters is the scale factor
p large 6
-------------- = ----------------
p small 5
Using cross products
6 p large = 5 p small
We know the sum is 226
p large + p small = 226
p large = 226 - p small
We have 2 equation and 2 unknowns
6 p large = 5 p small
Substitute for p large
6 (226 - p small) = 5 p small
1356 - 6 p small = 5 p small
Add 6 p small to each side
1356 = 11 p small
divide by 11
1356/11 = p small
P large = 226-1356/11
p large = 2486/11-1356/11
plarge = 1130/11
The solution requires whole number answers so
1356/11 = p small
123.27 which rounds to 123
plarge = 1130/11
plarge = 102.7272 = 103
