Answer:
Danny
Step-by-step explanation:
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(3x -1) (3x+1)
9x^2 - 1
Rewriting
(3x)^2 -1^2
This is the difference of squares a^2 -b^2 = (a+b) (a-b)
Integers
Counting Numbers are {1,2,3,4,5,...}
Its opposite would be -1,-2,-3,-4,-5,... respectively.
It includes 0 so the whole set would be
{ ..., -5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5, ... }
which is set of integers.
System of Linear Equations entered :
[1] y - 2x/3 = -1
[2] y + x = 4
// To remove fractions, multiply equations by their respective LCD
Multiply equation [1] by 3
// Equations now take the shape:
[1] 3y - 2x = -3
Graphic Representation of the Equations :
-2x + 3y = -3 x + y = 4
Solve by Substitution :
// Solve equation [2] for the variable x
[2] x = -y + 4
// Plug this in for variable x in equation [1]
[1] 3y - 2•(-y +4) = -3
[1] 5y = 5
// Solve equation [1] for the variable y
[1] y = 1
// By now we know this much :
y = 1
x = -y+4
// Use the y value to solve for x
x = -(1)+4 = 3
I hope this help you
(a⁴-b⁴)/(a-b)
using..(a+b²)=(a+b)(a-b)
=(a²+b²)(a²-b²)/(a-b)
=(a²+b²)(a+b)(a-b)/(a-b)
=(a²+b²)(a+b)
