<h3>
<u>Explanation</u></h3>
- Solve the equation for d-term.
Because we cannot subtract or add up constants and variables, we simply move the same variable term to the same side and constant term to the same constant side.
Substitute d = -11 in the equation.
The equation is true for d = -11.
<h3>
<u>Answer</u></h3>
<u>
</u>
Let x and y be the 2 parts of 15 ==> x + y=15 (given)
Reciprocal of x and y ==> 1/x +1/y ==> 1/x + 1/y = 3/10 (given)
Let's solve 1/x + 1/y = 3/10 . Common denominator = 10.x.y (reduce to same denominator)
==> (10y+10x)/10xy = 3xy/10xy ==> 10x+10y =3xy
But x+y = 15 , then 10x+10y =150 ==> 150=3xy and xy = 50
Now we have the sum S of the 2 parts that is S = 15 and
their Product = xy =50
Let's use the quadratic equation for S and P==> X² -SX +P =0
Or X² - 15X + 50=0, Solve for X & you will find:
The 1st part of 15 is 10 & the 2nd part is 5
Answer:
Step-by-step explanation:
Answer:
(a) We will form an equation of line from the points given (6,10) and (2,15)
Using:
On substituting the values in the formula above we will get the required equation of line.
On simplification we will get:
(b) We need to tell at day 0 put x=0 in above equation:
Anika worked for 70 hours on the set up crew on the day the fair arrived at the fairgrounds day 0.
Now, we need to tell decrease per day which is equal to the slope of line
To find the slope compare the equation with general equation which is y=mx+c where m is slope
Here, in
which is the decrease per day.
Answer:
`The answer is below
Step-by-step explanation:
P and q are points on the line y=2-4X. complete the coordinates of P and Q, P(0, ) Q( ,0)
Draw the line y= 2-4X for vales of x from -2 to 2
Solution:
The equation of a line is given by:
y = mx + b
Where y and x are variables, m is the slope of the line and b is the y intercept (that is value of y when x = 0).
The line of y = 2 - 4x is drawn by finding the corresponding values of y for x from -2 to 2 and plotting on a graph.
x: -2 -1 0 1 2
y: 10 6 2 -2 -6
The value P(0, ) Q( ,0)
The y coordinate of point P is gotten by substituting x = 0:
y = 2 - 4(0) = 2
P = (0, 2)
The x coordinate of point Q is gotten by substituting y = 0:
0 = 2 - 4x
4x = 2
x = 0.5
Q = (0.5, 0)
