There are 120 ways in which 5 riders and 5 horses can be arranged.
We have,
5 riders and 5 horses,
Now,
We know that,
Now,
Using the arrangement formula of Permutation,
i.e.
The total number of ways 
,
So,
For n = 5,
And,
r = 5
As we have,
n = r,
So,
Now,
Using the above-mentioned formula of arrangement,
i.e.
The total number of ways ,
Now,
Substituting values,
We get,
We get,
The total number of ways of arrangement = 5! = 5 × 4 × 3 × 2 × 1 = 120,
So,
There are 120 ways to arrange horses for riders.
Hence we can say that there are 120 ways in which 5 riders and 5 horses can be arranged.
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Answer:
$0.11
Step-by-step explanation:
Answer:
.85, .89,47/59
Step-by-step explanation:
.85 is the least number
.89 is the second number
and 47/50 is the greatest number
28oz=0.793787 kilograms
280z=793.787 grams
(in case you need to show work)
1oz=28.3495grams
1oz=0.0283495
Answer:
<h2>p(B) =
8310</h2>
Step-by-step explanation:
We will use the addition rule of probability of two events to solve the question. According to the rule given two events A and B;
p(A∪B) = p(A)+p(B) - p(A∩B) where;
A∪B is the union of the two sets A and B
A∩B is the intersection between two sets A and B
Given parameters
P(A)=15
P(A∪B)=1225
P(A∩B)=7100
Required
Probability of event B i.e P(B)
Using the expression above to calculate p(B), we will have;
p(A∪B) = p(A)+p(B) - p(A∩B)
1225 = 15+p(B)-7100
p(B) = 1225-15+7100
p(B) = 8310
Hence the missing probability p(B) is 8310.
