From the moment the friend passes the bicyclist, his friend covers a distance over time t of (3.63 m/s)*t.
The bicyclist covers a distance of 1/2*(2.11 m/s^2)*t^2. They meet when these distances are equal:
3.63 t = 1.055 t^2 ==> 1.055 t^2 - 3.63 t = 0
==> t = 0 s or t = 3.44 s
Answer:
If sin(4x–10)° = cos(40-x)°, then x = 20
Step-by-step explanation:
Answer:
approximately 27 grams
Work Shown:
Half life formula
y = A*(0.5)^(x/H)
where,
A = starting amount = 30 grams
H = half life period = 90 years
x = number of years that pass by = 12
y = amount left over after x years
Let's plug the values for x, A and H into the formula to find y
y = A*(0.5)^(x/H)
y = 30*(0.5)^(12/90)
y = 27.3516746567466
y = 27 .... rounding to the nearest whole number
Answer:
find out how many units higher g(x) is compared to f(x).
g(x) is 3 units higher than f(x)
Since the graph is 3 units higher, the value of k must be 3.
Step-by-step explanation:
ok i honestly hope i answerd this correctly because im terrible at reading math
"Completing the square" is the process used to derive the quadratic formula for the general quadratic ax^2+bx+c=0. Suppose you did not know the value of a,b, or c of the quadratic...
ax^2+bx+c=0 You need a leading coefficient of one for the process to work, so you divide the whole equation by a
x^2+bx/a+c/a=0 now you move the constant to the other side of the equation
x^2+bx/a=-c/a now you halve the linear coefficient, square that, then add that value to both sides, ie, (b/(2a))^2=b^2/(4a^2)...
x^2+bx/a+b^2/(4a^2)=b^2/(4a^2)-c/a now the left side is a perfect square...
(x+b/(2a))^2=(b^2-4ac)/(4a^2) now take the square root of both sides
x+b/(2a)=±√(b^2-4ac)/(2a) now subtract b/(2a) from both sides
x=(-b±√(b^2-4ac))/(2a)
It is actually much simpler keeping track of everything when using known values for a,b, and c, but the above explains the actual process used to create the quadratic formula, which the above solution is. :)
