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4 years ago

Prove that if BA=I then BA=AB.

Mathematics

1 answer:

Zanzabum4 years ago

4 0

Answer with Step-by-step explanation:

Since we have given that

$BA=I$

As we know that

AA⁻¹ = I (A is invertible matrix)

Multiplying A⁻¹ on the both the sides:

$BAA^{-1}=IA^{-1}\\\\B=A^{-1}$

Using the above result, we get that

$BA=I=AA^{-1}\\\\BA=AB$

Therefore, BA = AB

Hence, proved.

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The first discount on a camera was 18%. The second discount was 20%. After these two discounts the price was $328. What was the

Artyom0805 [142]

Answer:

$500

Step-by-step explanation:

We can find the original price of the camera through a proportion. A proportion is an equation where two ratios or fractions are equal. The ratios or fractions compare like quantities.

<u>Second Discount</u>

20% off means we paid 80%. We know we paid $328 of some price.

$\frac{80}{100} =\frac{328}{y}$

I can now cross-multiply by multiplying numerator and denominator from each ratio.

$80y=100(328)\\80y=32800$

I now solve for y by dividing by 80.

$\frac{80y}{80} =\frac{32800}{80} \\y= $410$

The price after the first discount was $410.

<u>First Discount</u>

We will repeat the steps above with $410. 18% off means we paid 82%.

$\frac{82}{100} =\frac{410}{y}$

I can now cross-multiply by multiplying numerator and denominator from each ratio.

$82y=100(410)\\82y=41000$

I now solve for y by dividing by 82.

$\frac{82y}{82} =\frac{41000}{82} \\y= $500$

The original price was $500.

5 0

3 years ago

Will give 5 stars on your answer and a thank you.

DENIUS [597]

Answer:

the variable term is (t)

the answer is 13.50t

4 0

2 years ago

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A cryptographic hash takes a message as input and produces a fixed-length string as output, called the digital fingerprint. A br

Allushta [10]

Answer:

$1.85x10^{19}$ attempts are required to find a matching pair if the digital fingerprint is 64 bits long.

$3.40*10^{38}$ attempts are required to find a matching pair if the digital fingerprint is 128 bits long.

Step-by-step explanation:

Each bit has two options. So

How many attempts are required to find a matching pair if the digital fingerprint is 64 bits long?

So for each of the 64 bits, we have the following number of options.

2 - 2 - 2 - 2 -... - 2

So, in all, there are

$T = 2^{64} = 1.85x10^{19}$

options.

So, $1.85x10^{19}$ attempts are required to find a matching pair if the digital fingerprint is 64 bits long.

128 bits long?

Using the same logic as the first question.

$T = 2^{128} = 3.40*10^{38}$

So, $3.40*10^{38}$ attempts are required to find a matching pair if the digital fingerprint is 128 bits long.

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3 years ago

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3 years ago

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sergij07 [2.7K]

Answer:

I think it is non proportional

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3 years ago

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