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timofeeve [1]
3 years ago
9

Unimart Precision Manufacturing

Business
1 answer:
Anarel [89]3 years ago
7 0

Answer:

Results are below.

Explanation:

Giving the following information:

Company 1:

Beginning inventory Merchandise $253,000

Cost of purchases 600,000

Ending inventory Merchandise 153,000

Company 2:

Beginning Finished goods $506,000

Cost of goods manufactured 930,000

Ending Finished goods 147,000

<u>To calculate the cost of goods sold, we need to use the following formula:</u>

<u></u>

COGS= beginning finished inventory + cost of goods manufactured/purchased - ending finished inventory

<u>Company 1:</u>

COGS= 253,000 + 600,000 - 153,000

COGS= $700,000

<u>Company 2:</u>

COGS= 506,000 + 930,000 - 147,000

COGS= $1,289,000

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The following data relate to labor cost for production of 22,000 cellular telephones:
Anuta_ua [19.1K]

Answer:

Results are below.

Explanation:

Giving the following information:

Production= 22,000 units

Actual: 4,220 hrs. at $44.50

Standard: 4,160 hrs. at $46.00

<u>To calculate the direct labor time and rate variance, we need to use the following formula:</u>

Direct labor time (efficiency) variance= (Standard Quantity - Actual Quantity)*standard rate

Direct labor time (efficiency) variance= (4,160 - 4,220)*46

Direct labor time (efficiency) variance= $2,760 unfavorable

Direct labor rate variance= (Standard Rate - Actual Rate)*Actual Quantity

Direct labor rate variance= (46 - 44.5)*4,220

Direct labor rate variance= $6,330 favorable

Total variance= 6,330 - 2,760

Total variance= $3,570 favorable

5 0
3 years ago
Click this link to view O*NET’s Work Context section for Human Resources Managers. Note that common contexts are listed toward t
Vika [28.1K]

Answer:

freedom to make decisions

electronic mail and telephone

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7 0
3 years ago
Read 2 more answers
Question 2: Allocating costs using ABC You have an ABC system with three pools number of cost driver units total cost in the poo
allochka39001 [22]

Answer:

Results are below.

Explanation:

<u>To calculate the activities rates, we need to use the following formula on each pool:</u>

Predetermined manufacturing overhead rate= total estimated overhead costs for the period/ total amount of allocation base

Pool 1= 20,000/10,000= $2 per direct labor dollar

Pool 2= 15,000/50= $300 per setup

Pool 3= 10,000/200= $50 per hour

<u>Now, we can allocate costs to each product:</u>

Allocated MOH= Estimated manufacturing overhead rate* Actual amount of allocation base

Product A:

Pool 1= 2*4,000= 8,000

Pool 2= 300*20= 6,000

Pool 3= 50 *50= 2,500

Total allocated costs= $16,500

Product B:

Pool 1= 2*6,000= 12,000

Pool 2= 300*30= 9,000

Pool 3= 50 *150= 7,500

Total allocated costs= $28,500

8 0
3 years ago
The reason fast food restaurants often are found in close proximity to each other is a. they enjoy competition b. location clust
olganol [36]

Answer:

b. location clustering near high traffic flows

Explanation:

Proximity to customers is a major consideration when deciding on a business location.  A business situated in areas with many potential customers has a high probability of succeeding. Restaurants are usually strategically situated in places with heavy customer flow.  

Restaurants may be established near offices, in market places, near public transport terminus, or other location convenient to customers.  With time, customers tend to associate that particular building, area, or street with restaurants. As the area becomes synonymous with restaurants, more customers will visit it, leading to more restaurants to open in that locality.

3 0
3 years ago
a bacteria population starts with 200 bacteriaa and grows at a rate of r(t) = (450.268)e 1.12567t bacteria per hour. How many ba
Virty [35]

Answer:

11,513

Explanation:

Data provided in the question:

Initial bacteria = 200

Growth rate r(t) = (450.268)e^{1.12567t}

Now,

Total growth after 3 hours = \int\limits^3_0 {(450.268)e^{1.12567t}} \, dt

or

Total growth after 3 hours = 450.268\int\limits^3_0 {e^{1.12567t}} \, dt

or

Total growth after 3 hours =450.268[\frac{e^{1.12567t}}{1.12567}]^3_0

[ ∵ \int{d(e^x)}{dt}=\frac{e^x}{\frac{dx}{dt}}]

Thus,

Total growth after 3 hours = 400 × [{e^{1.12567t}]^3_0

or

Total growth after 3 hours = 400 × [{e^{1.12567(3)}-e^{1.12567(0)}]

or

Total growth after 3 hours ≈ 11313

Hence,

Total bacteria after 3 hours = Initial bacteria + Total growth after 3 hours

= 200 + 11313

= 11,513

4 0
3 years ago
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