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Lerok [7]
3 years ago
14

Rewrite the equation

Mathematics
1 answer:
Mrac [35]3 years ago
5 0
Y^2-4


Explanation:
Divide y^3 by y. Subtract the exponents to get y^2. Divide 4 by -1 and you get -4.
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There is a triangular parking lot at the local mall. The second angle of the triangular parking lot is six more than twice as la
Travka [436]

Answer:

The measure of the three angles are;

The first angle is 62°

The second angle is 28°

The third angle is 90°

Step-by-step explanation:

The given information are;

The shape of the parking lot = Triangular

Let the angles of the triangle be given as follows

First angle = A

Second angle = B

Third angle = C

The given triangle interior angle dimensions are;

A = 6 + 2× B

C = A + B

However, we have;

A + B + C = 180° (Angle sum property for a triangle)

Therefore;

A + B + C = 180° gives;

C + C = 180° (Transitive property)

2·C = 180°

C = 180°/2 = 90°

C = 90°

However, C = A + B  therefore;

90° = A + B and, A = 6 + 2 × B, we get;

A + B = 90° (Symmetric property)

6 + 2× B + B = 90° (Substitution property)

6 + 3·B = 90°

3·B = 90° - 6° = 84°

B = 84°/3 = 28°

B = 28°

From, A = 6 + 2 × B, we have;

A = 6 + 2 × 28° = 62°

A = 62°

First angle = A = 62°

Second angle = B = 28°

Third angle = C = 90°

The measure of the three angles are;

First angle is 62°

Second angle is 28°

Third angle is 90°.

8 0
3 years ago
Verify that each of the following transformations preserves congruence and name the congruence transformation
AnnZ [28]

Pentagon A B C D E is reflected across the X-axis to form pentagon A B C D.


6 0
3 years ago
WILL GIVE BRAINLIEST& 15 PTS.
kicyunya [14]

Answer:

The given fraction \frac{x^3-x^2}{x^3} reduces to  \frac{x-1}{x}

Step-by-step explanation:

Consider the given fraction \frac{x^3-x^2}{x^3}

We have to reduce the fraction to the lowest terms.

Consider numerator x^3-x^2

We can take x² common from both the term,

Thus, numerator can be written as x^2(x-1)

Given expression can be rewritten as ,

\frac{x^3-x^2}{x^3}=\frac{x^2(x-1)}{x^3}

We can now cancel x^2 from both numerator and denominator,

\Rightarrow \frac{x^2(x-1)}{x^3}=\frac{x^2(x-1)}{x^2 \cdot x}

\Rightarrow \frac{(x-1)}{x^2 \cdot x}=\frac{x-1}{x}

Thus, the given fraction \frac{x^3-x^2}{x^3} reduces to  \frac{x-1}{x}

6 0
3 years ago
Read 2 more answers
What is the domain of f(x) 5^x-7?
kherson [118]
Domain is the set of number you can use for x we can use any number for x the domain is all real numbers answer is last one
3 0
3 years ago
What is the midpoint of the x-intercepts of<br> f(x) = (x – 2)(x – 4)?
emmasim [6.3K]

Answer:

(3,0)

Step-by-step explanation:

The axis of symmetry is midway between the roots

3 0
3 years ago
Read 2 more answers
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