B. -3 and 5
constants are the numbers without variables (the letters) and coefficients are the numbers with variables
X +x²= 132
x +x²-132= 132-132
x²+x -132 = 0
(x-11) (x+12) = 0
x-11 = 0 X+12=0
x-11+11 = 0+11 X+12-12=0-12
x =11 x= -12
Check
x +x²= 132 x +x²= 132
-12 +-12²= 132 11 +11²= 132
-12 + 144 = 132 11+ 121=132
132= 132 132=132
Since the problem says positive the answer is (11,121)
Answer:
option 4
Step-by-step explanation:
option 4 -1/7^12
So 1st, divide the shape into multiple other shapes.
BTW, sorry if I take long I'm trying to draw the lines on the picture.
Then, the area of a triangle in a=bh(1/2) and for trapezoids, it's (1/2(length of base 1+ length of base 2))height, so, do that for the 2 trapeziods, and do that for the triangles. I got 42.