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2 years ago

X and y are both bigger than 30. x and y have HCF 21 and LCM 1617. Find x and y.

Mathematics

1 answer:

Sunny_sXe [5.5K]2 years ago

6 0

The values of x and y are 99 and 343

The HCF of numbers is the highest common factors of the numbers

The LCM of numbers is the lowest common multiple of the numbers

The HCF and the LCM are given as:

$HCF = 21$

$LCM = 1617$

Multiply the HCF and the LCM

$HCF \times LCM = 21 \times 1617$

$HCF \times LCM = 33957$

The product of the numbers x and y equals the product of the HCF and the LCM.

So, we have:

$x \times y = 33957$

<h3>Prime Factors</h3>

Express 33957 as a prime factor

$x \times y = 3^2 \times 7^3 \times 11$

Rewrite the equation as

$x \times y = 99 \times 7^3$

$x \times y = 99 \times 343$

By comparison:

$x = 99$

$y= 343$

Hence, the values of x and y are 99 and 343

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7(4g) + 3(5h) +2(-3g) g=1/2, h=1/3

cluponka [151]

Answer:16

Step-by-step explanation:

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3 years ago

Name four fractions between 5/6 and 7/8

Nataly_w [17]

Answer:

101/120, 102/120, 103/120, and 104/120.

Step-by-step explanation:

First find the LCM of 6 and 8:24

So the two given fractions are 20/24, and 21/24

Since the the fractions will become decimals with the denominator 24, choose another denominator: 48

So the two given fractions are 40/48 and 42/48.

Even this denominator isn't possible so continue with different denominators.

As I notice, that each multiple increases by 1...

20-21, 40-42, 60-63, 80-84, and 100-105.

100-105 is the only numerator that has 4 numbers in-between so, the four fractions between 5/6 and 7/8 are: 101/120, 102/120, 103/120, and 104/120.

And the 2 given fractions are 100/120 and 105/120.

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3 years ago

Read 2 more answers

Suppose the number of hits a webpage receives follows a Poisson distribution. The average number of hits per minute is 2.4. What

REY [17]

Answer:

The probability that the page will get at least one hit during any given minute is 0.9093.

Step-by-step explanation:

Let <em>X</em> = number of hits a web page receives per minute.

The random variable <em>X</em> follows a Poisson distribution with parameter,

<em>λ</em> = 2.4.

The probability function of a Poisson distribution is:

$P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0,1,2,...$

Compute the probability that the page will get at least one hit during any given minute as follows:

P (X ≥ 1) = 1 - P (X < 1)

= 1 - P (X = 0)

$=1-\frac{e^{-2.4}(2.4)^{0}}{0!}\\=1-\frac{0.09072\times1}{1} \\=1-0.09072\\=0.90928\\\approx0.9093$

Thus, the probability that the page will get at least one hit during any given minute is 0.9093.

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3 years ago

What is the equation of the line that is perpendicular to the

kotegsom [21]

Answer:

y=x-6

Step-by-step explanation:

The x-intercept is found replacing y = 0, as follows:

<u>Function:</u> y = -3x + 8

x-intercept:

0 = -3x + 8

3x = 8

x = 8/3

<u>Function</u>: y = -3x + 6

x-intercept:

0 = -3x + 6

3x = 6

x = 6/3 = 2

<u>Function</u>: y = -x - 8

x-intercept:

0 = -x - 8

x = -8

<u>Function</u>: y = x - 6

x-intercept:

0 = x - 6

x = 6

The last option is the only one in which x-intercept is x = 6.

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3 years ago

The pair of triangles that are congruent by ASA criterion is

stealth61 [152]

Answer:

The pair of triangles that are congruent by the ASA criterion isΔ ABC and Δ XYZ.

The pair of triangles that are congruent by the SAS criterion is Δ BAC and ΔRQP.

Step-by-step explanation:

Two triangles are congruent by ASA property if any two angles and their included side are equal in both triangles .In triangles Δ ABC and Δ XYZ the equal side 5 is between the two equal angles. So these triangles are congruent by ASA criterion.

Two triangles are congruent by SAS if two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle .In triangles Δ BAC and ΔRQP. the included angles A and Q are equal and hence the triangles are congruent by SAS criterion.

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3 years ago