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Andrew [12]
3 years ago
5

Evaluate 0.1m+8-12n0.1m+8−12n0, point, 1, m, plus, 8, minus, 12, n when m=30m=30m, equals, 30 and n=\dfrac14n= 4 1 ​ n, equals,

start fraction, 1, divided by, 4, end fraction
Mathematics
2 answers:
Rom4ik [11]3 years ago
8 0

Answer:

8

Step-by-step explanation:

We are required to evaluate:

0.1m+8-12n

When m=30, n=\frac{1}{4}

Substituting these values into the expression, we have:

0.1m+8-12n=0.1(30)+8-12(\frac{1}{4})\\=3+8-\frac{12}{4}\\=3+8-3\\=8

allochka39001 [22]3 years ago
7 0

Evaluate 0.1m+8-12n0.1m+8−12n0, point, 1, m, plus, 8, minus, 12, n when m=30m=30m, equals, 30 and n=\dfrac14n= 4 1 ​ n, equals, start fraction, 1, divided by, 4, end fraction

Answer: 8

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In Exercises 37– 40, BD ⃗ bisects ∠ABC. Find m∠ABD,<br><br>m∠CBD, and m∠ABC.
MrRissso [65]

Answer:

37,  ABD = CBD = 44 degrees, and ABC = 88 degrees

38.  ABD = CBD = 24 degrees, and ABC = 48 degrees

39.  ABD = CBD = 65 degrees, and ABC = 130 degrees

40.  ABD = CBD =67 degrees, and ABC = 134 degrees

Step-by-step explanation:

Recall that when a segment bisects an angle, the angle is divided in equal parts then we have:

37.  

6 x + 14 = 3 x + 29

3 x = 19 - 14 = 15

x = 15/3

x = 5

then ABD = 6 (5) + 14 = 30 + 14 = 44 degrees

CBD must equal ABD , so CBD = 44 degrees

And the total angle ABC = 88 degrees

38.

3 x + 6 = 7 x - 18

24 = 4 x

x = 24/4 = 6

Then ABD = 3 (6) + 6 = 24 degrees. Also CBD = 24 degrees and ABC = 48 degrees

39.

- 4 x + 33 = 2 x + 81

- 6 x = 81 - 33

-6 x = 48

x = - 48/6

x = -8

Then ABD = -4 (-8) + 33 = 32 + 33 = 65 degrees

The also CBD = 65 degrees, and ABC = 130 degrees

40.

8 x + 35 = 11 x + 23

35 - 23 = 11 x - 8 x

12 = 3 x

x = 12/3

x = 4 degrees

Therefore:

ABD = 8 (4) + 35 = 32 + 35 = 67 degrees.

Then also CBD = 67 degrees, and ABC = 134 degrees

3 0
3 years ago
Can someone help me with this problem!
GalinKa [24]

C. -1

Hope this helps! :)

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2 years ago
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Answer:

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Step-by-step explanation:

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alexandr1967 [171]
It already is in simplest form because the numerator and denonimator don't have a common factor to then divide them by.
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Asked what the central limit theorem says, a student replies, As you take larger and larger samples from a population, the histo
Arada [10]

Answer:

A. No, the student is not right. The central limit theorem says nothing about the histogram of the sample values. It deals only with the distribution of the sample means.

Step-by-step explanation:

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