This is just to easy the correct answer is A
It is
(3-x)^2
i made sure it correct this time
Answer:
P____Q____R
PR= PQ+ QR
(14x-13) = (5x-2)+(6x+1)
14x-13= 11x – 1
14x – 11x = 13–1
3x = 12
x= 12/ 3
x= 4
PR= 14x – 13 = 14 (4) – 13 = 18 – 13= 5
If you want (PQ , QR ) this is the solution
PQ =5x-2=5(4)-2=20-2=18
QR =6x+1=6(4)+1=24+1=25
I hope I helped you^_^
The figure showing the construction is given below.
Steps for the construction of a circle through three points not on a straight line are as follows:
1. To create two lines, connect the points.
2. Create the line's perpendicular bisector.
3. Create the opposite line's perpendicular bisector.
4. The circle's center is where they intersect.
5. Draw your circle by placing the compass on the center point and adjusting its length to reach any point.
What happens if the points are parallel?
The circle traveling through all three points will have an infinite radius if the three points are collinear, or all situated on a straight line. Therefore, a practical circle cannot traverse three collinear locations. The two radii would be parallel and would never come together at a center if you tried the construction. We may claim that they do cross mathematically but at infinity.
Hence, after following the steps we obtain the circle.
Learn more about constructions here-
brainly.com/question/8778086
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Answer:

Step-by-step explanation:
Since f(x) and g(x) share the same top at (0,0), their difference is only a scale factor, so g(x) = ax² but we need to find a.
To find it, we use the given point of g, (2,1)
So g(2) = 1
meaning that
a·2² = 1
4a = 1
a = 1/4