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2 years ago

The amount or the strength of force is called its

Mathematics

2 answers:

coldgirl [10]2 years ago

5 0

The amount or the strength of force is named magnitude.

<h3>What is force?</h3>

Force is that the push or pull on an object with mass that causes it to alter its velocity. Force is an external agent capable of adjusting the state of rest or motion of a selected body. it's a magnitude and a direction.

<h3 /><h3>How to identify strength of force?</h3>

The term which is true is magnitude. The magnitude of a force is expressed within the SI unit of force called Newton. 1 Newton is that the force which might make an object of 1 kilogram mass to at a speed of 1 meter per second. Magnitude is essentially the most extent of size and also the direction of an object. Magnitude is employed as a typical think about vector and scalar quantities. Magnitude of earthquake is measured by Richter scale.

Hence the number or the strength of force is named its magnitude.

Learn more about force at brainly.com/question/12970081

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kvasek [131]2 years ago

5 0

$\huge\underline{\red{A}\green{n}\blue{s}\purple{w}\pink{e}\orange{r} →}$

The amount or the strength of force is called its magnitude.

Step-by-step explanation:

<h3>Hope it helps you !!</h3>

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valentina_108 [34]

By comparing all the options with the formula of sum of cubes and difference of cubes we get that $(x+4)\left(x^{2}-4 x+16\right)$ is sum of cubes

<h3>What is formula of sum of cubes and difference of cubes?</h3>

Formula of sum of cubes and difference of cubes are following

$(a+b)(a^2 -ab +b^2) = a^3+ b^3 \\\\\\(a - b)(a^2+ ab+ b^2) = a^3 - b^3$

(a)

$(x-4) \left(x^{2}+4 x-16\right)\\=(x-4) \left(x^{2}+4 x-4^2\right)\\\\$

by comparison with formula we can say that this is neither sum or nor difference of cubes.

(b)

$(x-1)\left(x^{2}-x+1\right)\\=(x-1)\left(x^{2}-x+1^2\right)$

by comparison with formula we can say that this is neither sum nor difference of cubes.

(c)

$(x+1)(x-1)=x^{2}-1^{2}\\$

we can say that this is neither sum nor difference of cube as it's difference of squares.

(d)

$(x+4)\left(x^{2}-4 x+16\right)\\\\(x+4)\left(x^{2}-4 x+4^2\right)$

by comparison with formula this is equal to

$x^{3}+4^{3}\\$

Hence this is sum of cubes

(e)

$(x+4)\left(x^{2}+4 x+16\right)\\(x+4)\left(x^{2}+4 x+4^2\right)$

by comparison with formula we can say that this is neither sum nor difference of cubes.

By comparing all the options with the formula of sum of cubes and difference of cubes we get that $(x+4)\left(x^{2}-4 x+16\right)$ is sum of cubes

To know more about cubes visit: brainly.com/question/107100

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Explain if 12.1 is rational or irrational

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of the odd number it would be 3/6 in other words 1/2 Step-by-step explanation:

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