Question

***PLEASE HELP***

Answer 1

The equation of the given circle is $(x-5)^{2}+(y-14)^{2}=16.$

Step-by-step explanation:

Step 1:

The equation of a circle with its center at (h, k) and a radius of r is given by

$(x-h)^{2}+(y-k)^{2}=r^{2}$

The h value is the x coordinate and the k value is the y coordinates, so (h, k) is (5, 14).

The radius is given as 4 so $r=4$ and $r^{2} = 16.$

Step 2:

By substituting the values we know, we get

So the equation of the given circle is

$(x-h)^{2}+(y-k)^{2}=r^{2}, (x-5)^{2}+(y-14)^{2}=16.$