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TEA [102]
3 years ago
10

Is (4, 8) a solution of y > 5x + 4?

Mathematics
1 answer:
lana66690 [7]3 years ago
8 0
This is not a solution. When plugged in, 
8 > 20 + 4.
8 > 24, which is not true. :)
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This is due tonight please help
CaHeK987 [17]

Answer:

81x^4

Step-by-step explanation:

With exponents, whatever is in the parentheses is multiplied by <u>itself</u> however many times the exponent says.

In this case, you would be solving 3 x 3 x 3 x 3 and (x)^4.

3^4 = 81 with x^4 gives you:

81x^4

Hope this helps you :)

8 0
2 years ago
Mindy conducts an experiment with three quarters. She counts the number of heads and tails for each flip of the three quarters.
valkas [14]

Answer:

i don't have the table so no one can answer

Step-by-step explanation:

4 0
3 years ago
PLEASE HELP
NeTakaya

Answer:

A rectangular prism in which BA = 20 and h = 6 has a volume of 120 units3; therefore, Shannon is correct

Step-by-step explanation:

step 1

Find the area of the base of the rectangular pyramid

we know that

The volume of the rectangular pyramid is equal to

V=\frac{1}{3}BH

where

B is the area of the base

H is the height of the pyramid

we have

V=40\ units^{3}

H=6\ units

substitute and solve for B

40=\frac{1}{3}B(6)

120=B(6)

B=120/6=20\ units^{2}

step 2

Find the volume of the rectangular prism with the same base area and height

we know that

The volume of the rectangular prism is equal to

V=BH

we have

B=20\ units^{2}

H=6\ units

substitute

V=(20)(6)=120\ units^{3}

therefore

The rectangular prism has a volume that is three times the size of the given rectangular pyramid. Shannon is correct

3 0
4 years ago
Is .2 the same as .2000
mihalych1998 [28]
Yes it dosent matter how many zeros are after the 2
8 0
3 years ago
Read 2 more answers
The mean amount purchased by a typical customer at Churchill’s Grocery Store is $23.50, with a standard deviation of $5.00. Assu
m_a_m_a [10]

Answer: 0.0170

Step-by-step explanation:

Given : The mean amount purchased by a typical customer at Churchill’s Grocery Store is $23.50, with a standard deviation of $5.00.

i.e. \mu=23.50

\sigma=5

We assume the distribution of amounts purchased follows the normal distribution.

Sample size : n=50

Let \overline{x} be the sample mean.

Formula : z=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}

Then, the probability that the sample mean is at least $25.00 will be :-

P(\overline{x}\geq\25.00)=P(\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}\geq\dfrac{25-23.50}{\dfrac{5}{\sqrt{50}}})\\\\=P(z\geq2.12)\\\\=1-P(z

Hence, the likelihood the sample mean is at least $25.00= 0.0170

5 0
3 years ago
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