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elena55 [62]
3 years ago
10

How do I expand 3(2y+1)

Mathematics
1 answer:
frozen [14]3 years ago
4 0

Answer:

Answer is 6y+3

Step-by-step explanation:

The working step is at the diagram above:))

Thanks for moderators for helping me with my answer:))

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A.
Varvara68 [4.7K]

Answer:

Angela, a proportion is two equal ratios, kinda like 3/4 = 6/8.

 

If we call the number of cars c, then our proportion is 3/10 = c/100.

 

Cross multiplying, we get 10c = 300.

 

Dividing both sides by 10, c = 30.

3 0
3 years ago
Read 2 more answers
The monthly output P of a light bulb factory is given by the formula P = 450LK, where L is the amount invested in labor and K th
Tems11 [23]

Answer:

C(p)  = 4,96 (in thousands of dollars)

l = 2980 $  invest in labor

k = 2980 $ invest in equipment

Step-by-step explanation:

Information we have:

Monthly output   P = 450*l*k       ⇒  k = P/450*l

But the production need to be 4000

Then k = 4000/450*l

Cost of production = l * k     (in thousands of dollars)

C(l)  =  l  + 4000/450*l

Taking derivatives (both members of the equation)

C´(l) = 1 - 400 /45*l²          ⇒ C´(l) = 0          ⇒ 1 - 400/45l²  = 0

45*l² -  400  = 0              ⇒  l²  = 400/45

l = 2.98 (in thousands of dollars)

l = 2980 $ And

k = 400/45*l           ⇒  k 400/45*2.98

k = 2.98  (in thousands of dollars)

C(p) = l + k

C(p)  =  2980 + 2980  

C(p)  = 5960 $

4 0
3 years ago
Determine the salary per pay period. Law Clerk: $48,950; weekly. Round to the nearest Hundredth.
Viktor [21]
49,000 is the nearest round to the hundredth to 48,950
4 0
2 years ago
As one of her chores staci must vacuum 1/2 of the house if she already has vacuumed 1/3 of her share tonight what part of the ho
bonufazy [111]
Given that S<span>taci must vacuum 1/2 of the house.

If she already has vacuumed 1/3 of her share tonight the part of the house she has vacumed is given by

\frac{1}{3} \ of \ \frac{1}{2} = \frac{1}{3} \times \frac{1}{2} = \frac{1}{6}

Therefore, she has vacuumed 1/6 of the house.
</span>
3 0
3 years ago
What is 6x^2-x-2 when factoring
lidiya [134]
6x^2-x-2   this is of the form ax^2+bx+c

jk=ac=-12 and j+k=b=-1 so j and k must be -4 and 3 so

6x^2+3x-4x-2

3x(2x+1)-2(2x+1)

(3x-2)(2x+1)
7 0
3 years ago
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