Answer:
![x^2\sqrt[3]{x}](https://tex.z-dn.net/?f=x%5E2%5Csqrt%5B3%5D%7Bx%7D)
Step-by-step explanation:
The relevant properties of exponents are ...
(a^b)(a^c) = a^(b+c)
(a^b)^c = a^(bc)
1/a^b = a^-b
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Your expression simplifies to ...
![\displaystyle x^{\frac{6}{3}+\frac{6}{9}-\frac{1}{3}}=x^{\frac{7}{3}}\\\\=x^2\sqrt[3]{x}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x%5E%7B%5Cfrac%7B6%7D%7B3%7D%2B%5Cfrac%7B6%7D%7B9%7D-%5Cfrac%7B1%7D%7B3%7D%7D%3Dx%5E%7B%5Cfrac%7B7%7D%7B3%7D%7D%5C%5C%5C%5C%3Dx%5E2%5Csqrt%5B3%5D%7Bx%7D)
Answer: The answer is 9 3/4.
Step-by-step explanation: When converting an improper fraction to a mixed number, the first step to take is figure out how many times the denominator goes into the numerator. The number 4 goes into 39
9 times(4 x 9 = 36). The remainder 3 becomes the numerator of the denominator 4, therefore 39/4 converted to a mixed number is 9 3/4.
The slope of the first equation is -2, you can see it right off.
the slope of the second equation is 2, notice both are in slope-intercept form.
both equations are the equations of a line, so is really just two lines.
because their slope differs, they're not parallel or equivalent, therefore, they lines do meet at some point, and one point only, and therefore, they have 1 solution only.
a system of equations with at least 1 solution, is a consistent system.
a consistent system with exactly 1 solution only, is not just consistent, but also independent.
Answer:
$1,300
Step-by-step explanation:
commission on the first $10,000
= 4/100 * 10000
= $400
remaining amount
= $28,000 - $10,000
= $18,000
commission on remaining $18,000
= 5/100 * 18000
= $900
total commission
= $400 + $900
= $1,300
<span>4(x+5) = 4x +5x
Simplify by distributing and combining like terms
</span>(4)(x)+(4)(5)=4x+5x
4x+20=4x+5x
4x+20=(4x+5x)
4x+20=9x
Subtract 9x from each side
4x+20−9x=9x−9x
5x+20=0
<span />
Subtract 20 from each side
−5x+20−20=0−20
−5x=−20
Divide each side by -5
-5x ÷ -5 = -20 ÷ -5
x = 4
P.S this was actually harder than most algebra problems, so don't beat yourself about it :D<span /><span /><span /><span /><span />
