(4x + 2y – 62) + (5y – 2 + 7x)+(-92 – 27

Identify the functions that are continuous on the set of real numbers and arrange them in ascending order of their limits as x t

Studentka2010 [4]

Answer:

g(x)<j(x)<k(x)<f(x)<m(x)<h(x)

Step-by-step explanation:

1. $f(x)=\frac{x^2+x-20}{x^2+4}$

The denominator of f is defined for all real values of x

Therefore, the function is continuous on the set of real numbers

$\lim_{x\rightarrow 5}\frac{x^2+x-20}{x^2+4}=\frac{25+5-20}{25+4}=\frac{10}{29}=0.345$

3. $h(x)=\frac{3x-5}{x^2-5x+7}$

$x^2-5x+7=0$

It cannot be factorize .

Therefore, it has no real values for which it is not defined .

Hence, function h is defined for all real values.

$\lim_{x\rightarrow 5}\frac{3x-5}{x^2-5x+7}=\frac{15-5}{25-25+7}=\frac{10}{7}=1.43$

2. $g(x)=\frac{x-17}{x^2+75}$

The denominator of g is defined for all real values of x.

Therefore, the function g is continuous on the set of real numbers

$\lim_{x\rightarrow 5}\frac{x-17}{x^2+75}=\frac{5-17}{25+75}=\frac{-12}{100}=-0.12$

4. $i(x)=\frac{x^2-9}{x-9}$

x-9=0

x=9

The function i is not defined for x=9

Therefore, the function i is not continuous on the set of real numbers.

5. $j(x)=\frac{4x^2-7x-65}{x^2+10}$

The denominator of j is defined for all real values of x.

Therefore, the function j is continuous on the set of real numbers.

$\lim_{x\rightarrow 5}\frac{4x^2-7x-65}{x^2+10}=\frac{100-35-65}{25+10}=0$

6. $k(x)=\frac{x+1}{x^2+x+29}$

$x^2+x+29=0$

It cannot be factorize .

Therefore, it has no real values for which it is not defined .

Hence, function k is defined for all real values.

$\lim_{x\rightarrow 5}\frac{x+1}{x^2+x+29}=\frac{5+1}{25+5+29}=\frac{6}{59}=0.102$

7. $l(x)=\frac{5x-1}{x^2-9x+8}$

$x^2-9x+8=0$

$x^2-8x-x+8=0$

$x(x-8)-1(x-8)=0$

$(x-8)(x-1)=0$

$x=8,1$

The function is not defined for x=8 and x=1

Hence, function l is not defined for all real values.

8. $m(x)=\frac{x^2+5x-24}{x^2+11}$

The denominator of m is defined for all real values of x.

Therefore, the function m is continuous on the set of real numbers.

$\lim_{x\rightarrow 5}\frac{x^2+5x-24}{x^2+11}=\frac{25+25-24}{25+11}=\frac{26}{36}=\frac{13}{18}=0.722$

g(x)<j(x)<k(x)<f(x)<m(x)<h(x)

6 0

3 years ago

Round 431,857 to the nearest ten thousand

Alex Ar [27]

Answer:

i don' think you can

Step-by-step explanation:

3 0

2 years ago

The prism shown has a volume of 35cm³. Work out the height of the triangular cross section. The length going back is 7cm and the

Gre4nikov [31]

Answer:

2.5 cm

Step-by-step explanation:

The volume of a triangular prism is cross section × length.

The cross section area is the triangle area. The triangle length is 4 cm, the height is not given. The length of the triangular prism is 7cm.

4 × h × 1/2 × 7 = 35

14h = 35

h = 35/14

h = 5/2

The height of the triangular cross section is 2.5 cm.

3 0

3 years ago

Help plz due in 20 min

ipn [44]

Answer:

$3\sqrt{7}$

Step-by-step explanation:

× $\sqrt{63} = \sqrt{9times7} \\\sqrt{9} = 3\\3\sqrt{7}$

4 0

3 years ago

Read 2 more answers

3 Caleb claims that when you multiply a number by 10, you can just write a 0 at the right end of the number. Caleb gives the exa

devlian [24]

Answer:

They are both correct

Step-by-step explanation:

It's interpretation of the concept. In common practice multiplying by 10 means you add a zero and that's what we teach 10 year olds. But what does adding a zero mean? It means adding a place value and that's what you learn when you are

So in both examples just add a decimal:

2.0 x 10 = 20.

0.2 x 10 = 2.0

In conclusion, it depends on the level of precision required in the discussion and the level of maturity as to who is correct in their examples. If you are teaching 3rd graders math, by all means you add a zero. If you are discussing physics you are shifting over a place value.

8 0

3 years ago

(4x + 2y – 62) + (5y – 2 + 7x)+(-92 – 27 – 3y)