Here is your answer
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the complete question is
Find two numbers whose difference is 46 and whose product is a minimum
Let
x------->larger number
y-------> smaller number
P-------> product of the two numbers
we know that
-----> equation 1
-----> equation 2
substitute equation 1 in equation 2
![P=x*[x-46]\\ P=x^{2} -46x](https://tex.z-dn.net/?f=%20P%3Dx%2A%5Bx-46%5D%5C%5C%20P%3Dx%5E%7B2%7D%20-46x%20)
using a graph tool
see the attached figure
Find the value of x for that the product P is a minimum
the vertex is the point 
that means, for 
the product is a minimum 
find the value of y

therefore
the answer is
the numbers are
and 
Answer:
3.25
Step-by-step explanation:
divide then add 3
Answer: 90
Step-by-step explanation:
if you multiply the number of times the house played each opponent
Since They played each of their 15 opponents 3 times (keyword 3 Times so you don’t get confused again)
It would be 15x3=45 this answer “45” is the amount of games they played
Now you times it by 2
45x2= 90