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3 years ago

Which is a possible turning point for the continuous function f(x)?

Mathematics

2 answers:

Sergio039 [100]3 years ago

6 0

Turning points:

All points on the function where function changes it's shape

At turning point , it will either go from increasing to decreasing or from decreasing to increasing

We can see hat

as x increase upto x=0

The value of y decreases

x-value: -6 , -4 , -2 , 0

y-value: 8 , 2, 0 , -2

But f(x) changes from -2 to -1 ..

so, it is increasing

so, function changes at x=0

that's why turning point is

(0,-2).............Answer

Finger [1]3 years ago

3 0

(0,-2) as that is the point when the value of fx at either side of it is greater than itself

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A^2+b^2=1305, a*b=648, a-b=?

luda_lava [24]

a - b is 9

Step-by-step explanation:

Step 1: Given a² + b² = 1305, a × b = 648. Find a - b using the identity for (a - b)²

⇒ (a - b)² = a² + b² - 2ab

⇒ (a - b)² = 1305 - 2 × 648 = 1305 - 1296 = 9

⇒ (a - b) = 9

7 0

3 years ago

Read 2 more answers

3x+4y=2 4x-4y=12 by using elimination

Sidana [21]

(+3x+4y=2)
(+4x-4y=12)
-----------------
7x = 14
-----------------
7
X=2

3(2)+4y=2
6+4y=2
4y=-4
Y=-1.
Or you can plug x into the other equation.

4(2)-4y=12
8-4y=12
-4y=4
Y=-1.

8 0

4 years ago

Heather left the hospital and drove toward the desert at an average speed of 35 km/h. Danielle left sometime later driving in th

elena55 [62]

Answer:

Danielle drove 3 hours

Step-by-step explanation:

Suppose Heather moved in the x direction.

Then Danielle moved in the opposite direction, that is, she moved in the -x direction.

Let's call $V_1$ , $x_1$ , $t_1$ at the speed, distance and time that I code Heather

Let's call $V_2$ , $x_2$ , $t_2$ at the speed, distance and time Danielle codes.

Observe the following diagram:

(x) Heather <------ $x_1$ --------- hospital ---------- $x_2$ -----------> Danielle (-x)

So:

$V_1 = 35\ km/h$

$t_1 = 4\ h$

$V_2 = 50\ km/h$

We know that after 4 hours the distance between Heather and Danielle was 290 km.

That is to say:

$x_2 + x_1 = 290\ km/h$

We know that $x_1= v_1t_1$

$x_1 = 35(4)$

$x_1 = 140\ km$

We already know $x_1$ , the distance from the hospital to Heather, so we can find $x_2$ and thus know $t_2$

So:

$x_2 = 290 - 140\\\\x_2 = 150\ km$

Then:

$t_2 = \frac{x_2}{v_2}\\\\t_2 = \frac{150}{50}\\\\t_2 = 3\ h$

7 0

3 years ago

A line with a slope of -7 passes through the points (4,5) and (5,g). What is the value of g?

Semmy [17]

Answer:

I think the answer would be -2 . hope it helps u .

7 0

3 years ago

Can someone and give me the right answer

kolezko [41]

The 1st option is your answer,

because to solve c, the -11 and 11 = 0, so your left with adding 23 and 11, then you divide -4 on both sides to get the variable (x) by itself

And for f, you only need to divide -4 on both sides to get x by itself.

6 0

3 years ago