To expand two terms such as these, we can use the method called FOIL (stands for First, Outer, Inner, Last). Here is what I mean:
We have two terms: (x - 2)(x - 1)
We should first multiply the First two terms of each term in order to complete the F stage:
(x)*(x) =

So then, we take the two outer terms and multiply them together to complete the O stage:
(x)*(-1) = -x
So far we have two things that we have calculated; at the end of the FOIL process we will have four.
To keep going with the FOIL, we now multiply the two inner terms to complete the I stage:
(-2)*(x) = -2x
Last but not least, we need to complete the L stage - so we multiply the two last terms of each term:
(-2)*(-1) = 2
Now that we have our four terms, let us add them together and combine like terms:

Since -x and -2x both have the x portion in common and they are added together, we can add them to create one single term:
-x + (-2x) = -3x
So now that we have our terms completed, we can combine into one polynomial equation:

or
1/6 (divide each by 2)
4/24 (multiply each by 2)
Answer: I linked the graph but the intersection point is x= -1
Step-by-step explanation:
Answer:
Option C is the correct answer.
Step-by-step explanation:
Since a random number generator is used to select a single number between 1 and 28, inclusively;
For a fair decision to be made during the process, the number of persons in the set must be a divisor of 28.
Let's list the divisors of 28:
The divisors of 28 are {1, 2, 4, 7, 14, 28}
The only option that contains one of the divisors is option C which is 7.
Answer:

Step-by-step explanation:
For this case we know that we have 12 cards of each denomination (hearts, diamonds, clubs and spades) because 12*4= 52
First let's find the number of ways in order to select 5 diamonds. We can use the combinatory formula since the order for this case no matter. The general formula for combinatory is given by:

So then 12 C5 would be equal to:

So we have 792 was in order to select 5 diamonds from the total of 12
Now in order to select 3 clubs from the total of 12 we have the following number of ways:

So then the numbers of ways in order to select 5 diamonds and 3 clubs are:
