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3 years ago

the probability of tossing a number cube numbered 1-6 and getting and even number that is greater than or equal to 2

1 answer:

4 0

2, 4, 6 --> numbers that are even and greater than 2 on a number cube

1, 3, 5 ---> numbers that are not even and/or not greater than 2 on a number cube

So the probability of getting a even number that is greater than or equal to 2 is 3/6, which reduces to 1/2.

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The sum of two consecutive numbers is 5. Find the equation representing the same.

serious [3.7K]

Answer:

Step-by-step explanation:

Let the smallest number = x

The next number will be x + 1

x + x + 1 = 5

2x + 1 = 5 This is likely the answer to the question although it could be the equation above.

7 0

3 years ago

Put the following equation of a line into slope-intercept form, simplifying all

Maurinko [17]

Answer:

y=-4/5 x + 7

Step-by-step explanation:

Subtract 8 x by 8 x. Do not put 8 x under 10 y or 70.

Then divide 10 by all of the terms.

Then you have: y= 7 - 8/10 x

But then you have to flip 7 and - 8/10 x

And get y= -8/10 x + 7

Simplified is y= 4/5 x + 7

REMEMBER: y=m x + b

M= Slope

B= y-intercept

6 0

3 years ago

stira [4]

Answer:

Step-by-step explanation:

Set up as a proportion:

$\frac{QR}{QP}=\frac{BA}{BC}$ , insert given values

$\frac{?}{12}=\frac{30}{36}$ , cross multiple

36*?=30*12

36*?=360, divide both sides by 36 to get the missing side (?) by itself

?=10

3 0

3 years ago

I NEED HELP PLSSSSS I WILL MARK BRAINLEIST <3

lidiya [134]

Answer:

I am pretty sure the anwser is A

3 0

3 years ago

Read 2 more answers

WILL GIVE BRAINLIEST AND 25 POINTS! Which of the following statements are true? Check all that apply. A. If any row of a square

sertanlavr [38]

Answer:

Option A, B and E

Step-by-step explanation:

Determinant = ad-bc

Let's look at the picture and solve all

Option A)

If the row ( c and d ) is zero, the determinant will be zero

=> a(0)-b(0)

=> 0-0

=> 0 (So, True)

Option B)

If a = b = c = d (Let's say 1), the determinant will be

=> (1)(1)-(1)(1)

=> 1-1

=> 0 (So, True)

Option C)

An Identity matrix is

=> $\left[\begin{array}{ccc}1&0\\0&1\end{array}\right]$

So , it's determinant will be

=> (1)(1)-(0)(0)

=> 1-0

=> 1 (So, False)

Option D)

The determinant with matrix will all positive numbers can be negative as well as positive. This is not necessary that it would be positive. (So, False)

Option E)

A zero matrix is

=> $\left[\begin{array}{ccc}0&0\\0&0\end{array}\right]$

So, it's determinant is:

=> (0)(0)-(0)(0)

=> 0-0

=> 0 (So,True)

5 0

3 years ago